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The p-type substrate in a monolithic circuit should be connected to
  • a)
    d.c. ground point
  • b)
    must be floating
  • c)
    The most negative voltage available in the circuit
  • d)
    The most positive voltage available in the circuit
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The p-type substrate in a monolithic circuit should be connected toa)d...
Explanation:

P-Type Substrate Connection in a Monolithic Circuit
In a monolithic circuit, the p-type substrate plays a crucial role in the overall performance and functionality of the circuit. It is essential to connect the p-type substrate to the most negative voltage available in the circuit. This connection is necessary for several reasons.

Reasons for Connecting to the Most Negative Voltage:
- Preventing Parasitic Bipolar Transistors: By connecting the p-type substrate to the most negative voltage, it helps in preventing the formation of parasitic bipolar transistors within the circuit. These parasitic devices can cause unwanted leakage currents and affect the circuit's operation.
- Enhancing Circuit Performance: Connecting the p-type substrate to the most negative voltage helps in improving the overall performance of the circuit by reducing substrate noise and enhancing signal integrity.
- Avoiding Latch-Up: Latch-up is a common issue in integrated circuits where parasitic thyristors are triggered, leading to a short circuit condition. By connecting the p-type substrate to the most negative voltage, it helps in avoiding latch-up situations.

Conclusion:
In conclusion, connecting the p-type substrate to the most negative voltage available in the circuit is essential for ensuring the proper operation, performance, and reliability of the monolithic circuit. It helps in preventing parasitic effects, improving signal integrity, and avoiding latch-up issues, ultimately contributing to the overall functionality of the circuit.
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The p-type substrate in a monolithic circuit should be connected toa)d.c. ground pointb)must be floatingc)The most negative voltage available in the circuitd)The most positive voltage available in the circuitCorrect answer is option 'C'. Can you explain this answer?
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