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A network function contains only poles whose real-parts are zero or negative. The network is
  • a)
    always stable.
  • b)
    stable, if the jω-axis poles are simple.
  • c)
    stable, if the jω-axis poles are at most of multiplicity 2.
  • d)
    always unstable.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A network function contains only poles whose real-parts are zero or ne...
Poles are at  can be zero or negative). The system will be stable if the poles at jω-axis are simple.
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A network function contains only poles whose real-parts are zero or ne...
W-axis is not enclosed by the poles in the right half-plane.c)unstable, if the jw-axis is enclosed by the poles in the right half-plane.d)unstable, if the jw-axis is enclosed by the poles in the left half-plane.

The correct answer is b) stable, if the jw-axis is not enclosed by the poles in the right half-plane.

Explanation: The stability of a network is determined by the locations of its poles in the complex plane. A pole with a negative real-part represents an exponentially decaying response, which contributes to the stability of the network.

If all the poles have real-parts that are either zero or negative, it means that there are no poles located in the right half-plane (where the real-part is positive). This implies that there are no poles that lead to exponential growth or instability in the network.

However, it is possible for the poles to be located on the imaginary axis (jw-axis). If the jw-axis is not enclosed by any of the poles in the right half-plane, then the network is stable. This is because the poles on the jw-axis do not contribute to exponential growth or instability.

Therefore, the network is stable if the jw-axis is not enclosed by the poles in the right half-plane.
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A network function contains only poles whose real-parts are zero or negative. The network isa)always stable.b)stable, if the jω-axis poles are simple.c)stable, if the jω-axis poles are at most of multiplicity 2.d)always unstable.Correct answer is option 'B'. Can you explain this answer?
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