Chemistry Exam > Chemistry Questions > Indicate the correct statement for a 1-L samp...
Start Learning for Free
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:
- a)The average translational KE per molecule is the same in N2 and CO2
- b)The rms speed remains constant for both N2 and CO2
- c)The density of N2 is less than that of CO2
- d)The total translation KE of both N2 and CO2 is the same
Correct answer is option 'A,C,D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at...
Answer:
Average translational KE per molecule:
The average translational KE per molecule is directly proportional to the temperature of the gas. Since both N2 and CO2 are at the same temperature, they have the same average translational KE per molecule.
Density of N2 and CO2:
The density of a gas is directly proportional to its molar mass and inversely proportional to its temperature and pressure. The molar mass of N2 is less than that of CO2, so the density of N2 is less than that of CO2. Therefore, option (c) is correct.
Total translational KE of N2 and CO2:
The total translational KE of a gas sample is directly proportional to its temperature and the number of molecules in the sample. Since both N2 and CO2 are at the same temperature and have the same volume, they have the same number of molecules. Therefore, the total translational KE of both N2 and CO2 is the same. Thus, option (d) is also correct.
RMS speed remains constant:
The root mean square (RMS) speed of a gas is directly proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Since N2 and CO2 are at the same temperature, their RMS speed will be the same only if their molar masses are the same. However, the molar mass of N2 is less than that of CO2, so the RMS speed of N2 is greater than the RMS speed of CO2. Therefore, option (b) is incorrect.
Conclusion:
Therefore, the correct options are (a), (c), and (d).
Average translational KE per molecule:
The average translational KE per molecule is directly proportional to the temperature of the gas. Since both N2 and CO2 are at the same temperature, they have the same average translational KE per molecule.
Density of N2 and CO2:
The density of a gas is directly proportional to its molar mass and inversely proportional to its temperature and pressure. The molar mass of N2 is less than that of CO2, so the density of N2 is less than that of CO2. Therefore, option (c) is correct.
Total translational KE of N2 and CO2:
The total translational KE of a gas sample is directly proportional to its temperature and the number of molecules in the sample. Since both N2 and CO2 are at the same temperature and have the same volume, they have the same number of molecules. Therefore, the total translational KE of both N2 and CO2 is the same. Thus, option (d) is also correct.
RMS speed remains constant:
The root mean square (RMS) speed of a gas is directly proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Since N2 and CO2 are at the same temperature, their RMS speed will be the same only if their molar masses are the same. However, the molar mass of N2 is less than that of CO2, so the RMS speed of N2 is greater than the RMS speed of CO2. Therefore, option (b) is incorrect.
Conclusion:
Therefore, the correct options are (a), (c), and (d).
Free Test
FREE
| Start Free Test |
Community Answer
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at...
B
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer?
Question Description
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer?.
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer?.
Solutions for Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer?, a detailed solution for Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? has been provided alongside types of Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Indicate the correct statement for a 1-L sample of N2(g) and CO2(g) at 298 K and 1 atm pressure:a)The average translational KE per molecule is the same in N2 and CO2b)The rms speed remains constant for both N2 and CO2c)The density of N2 is less than that of CO2d)The total translation KE of both N2 and CO2 is the sameCorrect answer is option 'A,C,D'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup