Chemistry Exam > Chemistry Questions > Indicate the correct statement for equal volu...
Start Learning for Free
Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:
- a)The average translat ional K.E. per molecule is the same for N2 and CO2
- b)The density of N2 is less than that of CO2
- c)All of these
- d)The total translational K.E. of both N2 and CO2 is the same
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Indicate the correct statement for equal volume of N2(g) and CO2(g) at...
Explanation:
The correct statement for equal volume of N2(g) and CO2(g) at 25C and 1 atm is that the density of N2 is less than that of CO2.
Reasoning:
The density of a gas is directly proportional to its molecular weight. The molecular weight of N2 is 28 g/mol, whereas the molecular weight of CO2 is 44 g/mol. Since the molecular weight of CO2 is greater than that of N2, the density of CO2 is greater than that of N2.
The average translational K.E. per molecule is the same for N2 and CO2:
The average translational kinetic energy per molecule is given by the formula:
1/2 mv2 = (3/2) kT
Where m is the mass of the molecule, v is its velocity, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the mass of the molecules are the same for both N2 and CO2, the average translational kinetic energy per molecule is also the same.
The rms speed remains same for both N2 and CO2:
The root-mean-square (rms) speed of a gas molecule is given by the formula:
vrms = √(3kT/m)
Where m is the mass of the molecule, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the mass of the molecules are the same for both N2 and CO2, the rms speed of the molecules is also the same.
The total translational K.E. of both N2 and CO2 is the same:
The total translational kinetic energy of a gas is given by the formula:
KE = (3/2) NkT
Where N is the number of molecules, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the number of molecules are the same for both N2 and CO2, the total translational kinetic energy of both gases is the same.
Conclusion:
Hence, the correct statement for equal volume of N2(g) and CO2(g) at 25C and 1 atm is that the density of N2 is less than that of CO2.
The correct statement for equal volume of N2(g) and CO2(g) at 25C and 1 atm is that the density of N2 is less than that of CO2.
Reasoning:
The density of a gas is directly proportional to its molecular weight. The molecular weight of N2 is 28 g/mol, whereas the molecular weight of CO2 is 44 g/mol. Since the molecular weight of CO2 is greater than that of N2, the density of CO2 is greater than that of N2.
The average translational K.E. per molecule is the same for N2 and CO2:
The average translational kinetic energy per molecule is given by the formula:
1/2 mv2 = (3/2) kT
Where m is the mass of the molecule, v is its velocity, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the mass of the molecules are the same for both N2 and CO2, the average translational kinetic energy per molecule is also the same.
The rms speed remains same for both N2 and CO2:
The root-mean-square (rms) speed of a gas molecule is given by the formula:
vrms = √(3kT/m)
Where m is the mass of the molecule, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the mass of the molecules are the same for both N2 and CO2, the rms speed of the molecules is also the same.
The total translational K.E. of both N2 and CO2 is the same:
The total translational kinetic energy of a gas is given by the formula:
KE = (3/2) NkT
Where N is the number of molecules, k is the Boltzmann constant, and T is the temperature in kelvin. Since the temperature and the number of molecules are the same for both N2 and CO2, the total translational kinetic energy of both gases is the same.
Conclusion:
Hence, the correct statement for equal volume of N2(g) and CO2(g) at 25C and 1 atm is that the density of N2 is less than that of CO2.
Free Test
FREE
| Start Free Test |
Community Answer
Indicate the correct statement for equal volume of N2(g) and CO2(g) at...
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer?
Question Description
Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer?.
Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Indicate the correct statement for equal volume of N2(g) and CO2(g) at 25°C and 1 atm:a)The average translat ional K.E. per molecule is the same for N2 and CO2b)The density of N2 is less than that of CO2c)All of thesed)The total translational K.E. of both N2 and CO2 is the sameCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup