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A certain moving arm disk storage with one head has following specifications:
Number of tracks/recording surface = 200
Disk rotation speed = 2400 rpm
Track storage capacity = 62500 bits
The average latency time (assume that the head can move from one track to another only by traversing the entire track) is
  • a)
    2.5 s
  • b)
    2.9 s
  • c)
    3.1 s
  • d)
    3.6 s
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A certain moving arm disk storage with one head has following specific...
To cover 2400 x 62500 bits, 60 s are needed. Average latency time is the time needed to traverse 100 tracks i.e. 100 x 62500 bits, which is 2.5 s.
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Most Upvoted Answer
A certain moving arm disk storage with one head has following specific...
To calculate the average latency time for a moving arm disk storage system, we need to consider the time it takes for the head to move from one track to another and the time it takes for the desired track to rotate under the head.

Given specifications:
- Number of tracks/recording surface = 200
- Disk rotation speed = 2400 rpm
- Track storage capacity = 62500 bits

Let's calculate the average latency time step by step:

1. Time to rotate one track:
The time it takes for one track to rotate under the head can be calculated using the formula:
Time to rotate one track = 1 / (Disk rotation speed / Number of tracks)
= 1 / (2400 rpm / 200) = 1 / 12 rpm = 5 ms

2. Time to move from one track to another:
Since the head can only move from one track to another by traversing the entire track, we need to consider the time it takes to move from the current track to the desired track.
The head needs to travel a distance equal to the number of tracks it needs to move. Assuming the head moves at a constant speed, the time it takes to move from one track to another can be calculated as:
Time to move from one track to another = (Number of tracks / 2) * Time to rotate one track
= (200 / 2) * 5 ms = 100 * 5 ms = 500 ms

3. Average latency time:
The average latency time is the sum of the time it takes for the desired track to rotate under the head and the time it takes to move from the current track to the desired track.
Average latency time = Time to rotate one track + Time to move from one track to another
= 5 ms + 500 ms = 505 ms

Converting the average latency time to seconds:
Average latency time = 505 ms / 1000 ms/s = 0.505 s

Therefore, the correct answer is option 'A': 2.5 s.

Note: There seems to be an error in the given answer. The correct average latency time is 0.505 s, not 2.5 s.
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A certain moving arm disk storage with one head has following specifications:Number of tracks/recording surface = 200Disk rotation speed = 2400 rpmTrack storage capacity = 62500 bitsThe average latency time (assume that the head can move from one track to another only by traversing the entire track) isa)2.5 sb)2.9 sc)3.1 sd)3.6 sCorrect answer is option 'A'. Can you explain this answer?
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