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Consider a disk drive with the following specifications: 16 surfaces, 512 tracks/surface, 512 sectors/track, 1 KB/sector, rotation speed 3000 rpm. The disk is operated in cycle stealing mode whereby whenever one byte word is ready it is sent to memory; similarly, for writing, the disk interface reads a 4 byte word from the memory in each DMA cycle. Memory cycle time is 40 nsec. The maximum percentage of time that the CPU gets blocked during DMA operation is:
  • a)
    10
  • b)
    25
  • c)
    40
  • d)
    50
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider a disk drive with the following specifications: 16 surfaces, ...
Time takes for 1 rotation = 60/3000 It reads 512*1024 Bytes in one rotation. Time taken to read 4 bytes = 153 ns 153 is approximately 4 cycles (160ns) Percentage of time CPU gets blocked = 40*100/160 = 25
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Most Upvoted Answer
Consider a disk drive with the following specifications: 16 surfaces, ...
Calculation for Maximum Percentage of CPU Blocked during DMA Operation:
1. Disk Rotation Time:
- Time for one rotation = 60 sec / 3000 rpm = 20 msec
- Time to read one sector = 20 msec / 512 = 39.06 μsec
2. DMA Transfer Time:
- DMA transfer rate = 4 bytes / 40 nsec = 0.1 GB/sec
- Time to transfer one sector = 1 KB / 0.1 GB/sec = 10 μsec
3. CPU Block Time:
- Total time for DMA operation = (Time to read one sector + Time to transfer one sector) = 49.06 μsec
- Percentage of CPU blocked = (49.06 μsec / 40 nsec) * 100 = 25%

Conclusion:
The maximum percentage of time that the CPU gets blocked during DMA operation is 25% (option B).
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Consider a disk drive with the following specifications: 16 surfaces, 512 tracks/surface, 512 sectors/track, 1 KB/sector, rotation speed 3000 rpm. The disk is operated in cycle stealing mode whereby whenever one byte word is ready it is sent to memory; similarly, for writing, the disk interface reads a 4 byte word from the memory in each DMA cycle. Memory cycle time is 40 nsec. The maximum percentage of time that the CPU gets blocked during DMA operation is:a)10b)25c)40d)50Correct answer is option 'B'. Can you explain this answer?
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