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A 6-pole dc machine has 300 conductors and flux per pole is 15 mWb, If the machine Is driven at 1800 rpm, then the average emf induced per conductor will be
  • a)
    3.6 V
  • b)
    2.7 V
  • c)
    9 V
  • d)
    162 V
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A 6-pole dc machine has 300 conductors and flux per pole is 15 mWb, If...
Given, speed,
N= 1800 rpm 
n = 1800/60 rps = 30 rps
Average emf induced per conductor 
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Most Upvoted Answer
A 6-pole dc machine has 300 conductors and flux per pole is 15 mWb, If...
Given data:
Number of poles (p) = 6
Number of conductors (N) = 300
Flux per pole (φ) = 15 mWb
Speed of the machine (N) = 1800 rpm

To find: Average emf induced per conductor

Formula:
The average emf induced per conductor in a DC machine is given by the formula:

E = (φ * N * p) / 60 A

where E is the average emf induced per conductor,
φ is the flux per pole,
N is the speed of the machine in rpm,
p is the number of poles, and
A is the number of parallel paths.

Since it is a DC machine, the number of parallel paths (A) is equal to 1.

Calculation:
Substituting the given values into the formula:

E = (15 mWb * 300 * 6) / (60 * 1) V
E = (15 * 300 * 6) / 60 V
E = 2700 / 60 V
E = 45 V

However, the question asks for the average emf induced per conductor, so we need to divide the result by the number of conductors (N).

Average emf induced per conductor = E / N
Average emf induced per conductor = 45 V / 300
Average emf induced per conductor = 0.15 V

Therefore, the average emf induced per conductor in the given 6-pole DC machine is 0.15 V, which is equivalent to 2.7 V (rounded to one decimal place).

Hence, the correct answer is option B) 2.7 V.
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it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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A 6-pole dc machine has 300 conductors and flux per pole is 15 mWb, If the machine Is driven at 1800 rpm, then the average emf induced per conductor will bea)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer?
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