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The value of  by Stoke’s theorem, where   and C is the boundary of the triangle with vertices at ( 0 ,0 , 0 ) , ( 1 , 0 , 0 ) and ( 1 ,1 , 0 ) is
  • a)
    1/2
  • b)
    1/3
  • c)
    1/4
  • d)
    1/5
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The value ofby Stoke’s theorem, whereand C is the boundary of th...

We have, curl 

Also we note that z coordinate of each vertex of the triangle is zero.
or The triangle lies in the xy-plane. So, 
So, curl 
In the figure, we have only considered the xy-plane. So, by Stoke’s Theorem

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Most Upvoted Answer
The value ofby Stoke’s theorem, whereand C is the boundary of th...

We have, curl 

Also we note that z coordinate of each vertex of the triangle is zero.
or The triangle lies in the xy-plane. So, 
So, curl 
In the figure, we have only considered the xy-plane. So, by Stoke’s Theorem

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The value ofby Stoke’s theorem, whereand C is the boundary of thetriangle with vertices at ( 0 ,0 , 0 ) , ( 1 , 0 , 0 ) and ( 1 ,1 , 0 ) isa)1/2b)1/3c)1/4d)1/5Correct answer is option 'B'. Can you explain this answer?
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The value ofby Stoke’s theorem, whereand C is the boundary of thetriangle with vertices at ( 0 ,0 , 0 ) , ( 1 , 0 , 0 ) and ( 1 ,1 , 0 ) isa)1/2b)1/3c)1/4d)1/5Correct answer is option 'B'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about The value ofby Stoke’s theorem, whereand C is the boundary of thetriangle with vertices at ( 0 ,0 , 0 ) , ( 1 , 0 , 0 ) and ( 1 ,1 , 0 ) isa)1/2b)1/3c)1/4d)1/5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value ofby Stoke’s theorem, whereand C is the boundary of thetriangle with vertices at ( 0 ,0 , 0 ) , ( 1 , 0 , 0 ) and ( 1 ,1 , 0 ) isa)1/2b)1/3c)1/4d)1/5Correct answer is option 'B'. Can you explain this answer?.
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