Determine algebraically the vertices of Triangle formed by the lines 2...
The given equations of the sides of triangle are,
2x - y = 9 , 2x - 3y = 9 , x = 0 (y-axis)
The vertices are obtained by solving the equations two at a time
Solving equations (1) and (2):
2x - y = 2x - 3y = 9
=> 2y = 0 (or) y = 0
=> x = 9/2
Solving (1) and (3):
2x - y = 9 and x = 0
=> y = -9
Solving (2) and (3):
2x - 3y = 9 and x = 0
=> y =9/-3 = -3
Therefore the vertices are A(9/2,0), B(0,-9) and C(0,-3)
Determine algebraically the vertices of Triangle formed by the lines 2...
Problem: Determine algebraically the vertices of Triangle formed by the lines 2 x minus y is equals to 2 x minus 3 Y is equals to 9 and y-axis?
Solution:
Step 1: Find the intersection points of the given lines.
We have two equations:
2 x - y = 9 ...(1)
2 x - 3 y = 9 ...(2)
To find the intersection of these two lines, we need to solve these equations simultaneously.
Subtracting Equation (1) from Equation (2), we get:
-2y = 0
y = 0
Substituting y = 0 in Equation (1), we get:
2x - 0 = 9
x = 4.5
So, the first intersection point is (4.5, 0).
Substituting y = 0 in Equation (2), we get:
2x - 3(0) = 9
x = 4.5
So, the second intersection point is also (4.5, 0).
Step 2: Find the third vertex of the triangle.
The third vertex lies on the y-axis. Therefore, its x-coordinate is zero.
Substituting x = 0 in Equation (1), we get:
2(0) - y = 9
y = -9
So, the third vertex is (0, -9).
Step 3: Plot the vertices and draw the triangle.
The three vertices of the triangle are:
(4.5, 0), (4.5, 0), and (0, -9)
Plotting these points on the graph and drawing a line to connect them, we get the triangle.
The vertices of the triangle are:
(4.5, 0), (4.5, 0), and (0, -9)
Note: The two vertices (4.5, 0) are the same point, so the triangle is actually a straight line.
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