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Three particles each of mass m are kept at vertices of an equilateral triangle of side L. The gravitational field at centre due to these particles is :
  • a)
  • b)
    0
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Three particles each of massmare kept at vertices of an equilateral tr...
Let us put a test mass mat the center. Forces acting on it are 

These forces are of equal magnitude and act at 120° with each other .
Hence, 
∴ Fg = 0
The correct answer is: 0
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Most Upvoted Answer
Three particles each of massmare kept at vertices of an equilateral tr...
Gravitational field Eg.= -GM/r² (r^).As it is a vector quantity the resultant field due to two masses 'm'
will be cancelled out by the other field produced by a single particle mass 'm'.So, the effective gravitational field would be zero.
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Community Answer
Three particles each of massmare kept at vertices of an equilateral tr...
Let us put a test mass mat the center. Forces acting on it are 

These forces are of equal magnitude and act at 120° with each other .
Hence, 
∴ Fg = 0
The correct answer is: 0
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Three particles each of massmare kept at vertices of an equilateral triangle of sideL.The gravitational field at centre due to these particles is :a)b)0c)d)Correct answer is option 'B'. Can you explain this answer?
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