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Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O is
- a)1/p
- b)1/pn
- c)1 - pn
- d)pn
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Suppose that a process spends a fraction p of its time in I/O wait sta...
Considering that a process spends a fraction p of its time in I/O wait state. As n processes are there is memory at once, then Probability that all n processes are waiting for I/O = p x p x p x ... p (n times) = pn
Note: Moreover, the CPU utilization is given by the formula CPU utilization = 1 - pn.
Note: Moreover, the CPU utilization is given by the formula CPU utilization = 1 - pn.
Most Upvoted Answer
Suppose that a process spends a fraction p of its time in I/O wait sta...
Probability that a process is waiting for I/O
- Let's consider a single process. The probability that it is in I/O wait state at any given time is p.
- Therefore, the probability that it is not in I/O wait state is 1-p.
Probability that n processes are waiting for I/O
- Let's assume there are n processes in memory at once.
- We want to find the probability that all n processes are waiting for I/O.
- Since each process is independent, we can multiply the probabilities of each process waiting for I/O to get the probability that all n processes are waiting for I/O.
- Therefore, the probability that all n processes are waiting for I/O is (p)^n.
Probability that at least one process is not waiting for I/O
- The complement of the probability that all processes are waiting for I/O is the probability that at least one process is not waiting for I/O.
- Therefore, the probability that at least one process is not waiting for I/O is 1 - (p)^n.
Probability that all processes are not waiting for I/O
- The probability that all processes are not waiting for I/O is the complement of the probability that at least one process is not waiting for I/O.
- Therefore, the probability that all processes are not waiting for I/O is (p)^n.
Conclusion
- The probability that all n processes are waiting for I/O is (p)^n.
- The probability that all processes are not waiting for I/O is (p)^n.
- The probability that at least one process is not waiting for I/O is 1 - (p)^n.
- Therefore, the correct answer is option D - pn.
- Let's consider a single process. The probability that it is in I/O wait state at any given time is p.
- Therefore, the probability that it is not in I/O wait state is 1-p.
Probability that n processes are waiting for I/O
- Let's assume there are n processes in memory at once.
- We want to find the probability that all n processes are waiting for I/O.
- Since each process is independent, we can multiply the probabilities of each process waiting for I/O to get the probability that all n processes are waiting for I/O.
- Therefore, the probability that all n processes are waiting for I/O is (p)^n.
Probability that at least one process is not waiting for I/O
- The complement of the probability that all processes are waiting for I/O is the probability that at least one process is not waiting for I/O.
- Therefore, the probability that at least one process is not waiting for I/O is 1 - (p)^n.
Probability that all processes are not waiting for I/O
- The probability that all processes are not waiting for I/O is the complement of the probability that at least one process is not waiting for I/O.
- Therefore, the probability that all processes are not waiting for I/O is (p)^n.
Conclusion
- The probability that all n processes are waiting for I/O is (p)^n.
- The probability that all processes are not waiting for I/O is (p)^n.
- The probability that at least one process is not waiting for I/O is 1 - (p)^n.
- Therefore, the correct answer is option D - pn.
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Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer?
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Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer?.
Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose that a process spends a fraction p of its time in I/O wait state. With n processes in memory at once, the probability that all n processes are waiting for I/O isa)1/pb)1/pnc)1 - pnd)pnCorrect answer is option 'D'. Can you explain this answer?.
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