JEE Exam > JEE Questions > A 27 mW laser beam has a cross-sectional area...
Start Learning for Free
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space ∈0 = 9 × 10-12 SI units, Speed of light c = 3 × 108 m/s]:-
- a)1 kV/m
- b)2 kV/m
- c)1.4 kV/m
- d)0.7 kV/m
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude...
Intensity of EM wave is given by
Most Upvoted Answer
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude...
The magnitude of the maximum electric field in an electromagnetic wave can be calculated using the formula:
E = sqrt(2P / (c * ε * A))
Where:
E = magnitude of the maximum electric field
P = power of the laser beam (in Watts)
c = speed of light in vacuum (approximately 3 x 10^8 m/s)
ε = permittivity of space (approximately 8.854 x 10^-12 F/m)
A = cross-sectional area of the laser beam (in m^2)
Plugging in the given values:
P = 27 mW = 27 x 10^-3 W
A = 10 mm^2 = 10 x 10^-6 m^2
ε = 8.854 x 10^-12 F/m
E = sqrt(2 * (27 x 10^-3) / (3 x 10^8 * 8.854 x 10^-12 * 10 x 10^-6))
E = sqrt(54 x 10^-3 / (26.562 x 10^-12))
E = sqrt(2.0354 x 10^9)
E ≈ 45,136.3 V/m
Therefore, the magnitude of the maximum electric field in this electromagnetic wave is approximately 45,136.3 V/m.
E = sqrt(2P / (c * ε * A))
Where:
E = magnitude of the maximum electric field
P = power of the laser beam (in Watts)
c = speed of light in vacuum (approximately 3 x 10^8 m/s)
ε = permittivity of space (approximately 8.854 x 10^-12 F/m)
A = cross-sectional area of the laser beam (in m^2)
Plugging in the given values:
P = 27 mW = 27 x 10^-3 W
A = 10 mm^2 = 10 x 10^-6 m^2
ε = 8.854 x 10^-12 F/m
E = sqrt(2 * (27 x 10^-3) / (3 x 10^8 * 8.854 x 10^-12 * 10 x 10^-6))
E = sqrt(54 x 10^-3 / (26.562 x 10^-12))
E = sqrt(2.0354 x 10^9)
E ≈ 45,136.3 V/m
Therefore, the magnitude of the maximum electric field in this electromagnetic wave is approximately 45,136.3 V/m.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer?
Question Description
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer?.
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by [Given permittivity of space∈0 = 9 × 10-12 SI units, Speed of lightc = 3 × 108 m/s]:-a)1 kV/mb)2 kV/mc)1.4 kV/md)0.7 kV/mCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup