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A moving iron instrument gives full scale deflection with 10 mA has a resistance of 3W. Determine the resistance to be connected in series so as to enable it to read up to 100V
  • a)
    4218 W
  • b)
    8321 W
  • c)
    8194 W
  • d)
    9997 W
Correct answer is option 'D'. Can you explain this answer?
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To enable the moving iron instrument to read up to 100V, a series resistance needs to be connected. Let's determine the value of this resistance.

Given data:
Full-scale deflection current (I) = 10 mA
Resistance of the moving iron instrument (R) = 3 Ω
Full-scale deflection voltage (V) = 100 V

Using Ohm's law, we can determine the current flowing through the instrument at full-scale deflection:

I = V/R

Substituting the given values:

10 mA = 100 V / 3 Ω

We can rearrange this equation to find the resistance required for a full-scale deflection of 100V:

R = V/I

Substituting the given values:

R = 100V / 10 mA = 10000 Ω

Now, we need to determine the additional resistance to be connected in series with the moving iron instrument. Let's call this resistance R₂.

The total resistance (R_total) when the instrument reads full-scale deflection is given by:

R_total = R + R₂

Substituting the values:

10000 Ω = 3 Ω + R₂

Simplifying the equation:

R₂ = 10000 Ω - 3 Ω = 9997 Ω

Therefore, the resistance to be connected in series to enable the moving iron instrument to read up to 100V is 9997 Ω.

Hence, the correct answer is option D) 9997 Ω.
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