In a chemical reaction,theinitial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction isa)1b)16c)4d)1/4Correct answer is option 'C'. Can you explain this answer?

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In a chemical reaction,

the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is

a)
1
b)
16
c)
4
d)
1/4

Correct answer is option 'C'. Can you explain this answer?

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In a chemical reaction,theinitial concentration of B was 1.5 times of ...

given

3 – 2x = 2 – x
⇒ x = 1

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In a chemical reaction,theinitial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction isa)1b)16c)4d)1/4Correct answer is option 'C'. Can you explain this answer?

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In a chemical reaction,theinitial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction isa)1b)16c)4d)1/4Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a chemical reaction,theinitial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction isa)1b)16c)4d)1/4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a chemical reaction,theinitial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction isa)1b)16c)4d)1/4Correct answer is option 'C'. Can you explain this answer?.

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