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A 4-pole 500V shunt motor has 720 wave connected conductors on its armature. The fullload armature current is 60A and flux per pole is 0.03 Wb. The armature resistance is 0.2 Wand the contact drop per brush is 1V. What is the back emf ?
  • a)
    490V
  • b)
    460V
  • c)
    445V
  • d)
    486V
Correct answer is option 'D'. Can you explain this answer?
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A 4-pole 500V shunt motor has 720 wave connected conductors on its arm...
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A 4-pole 500V shunt motor has 720 wave connected conductors on its arm...
Given parameters:
- Number of poles (P) = 4
- Rated voltage (V) = 500V
- Number of armature conductors (Z) = 720
- Armature current (Ia) = 60A
- Flux per pole (Φ) = 0.03 Wb
- Armature resistance (Ra) = 0.2 Ω
- Contact drop per brush (Vb) = 1V

Calculate back emf (Eb).

Formula:
Back emf (Eb) = (PΦZN)/60A
where,
N = speed in RPM

1. Calculate speed (N) from back emf equation:
Eb = (PΦZN)/60A
N = (Eb x 60A)/(PΦZ)
N = (500 - 2Vb)/(PΦ/2π)(Z/2)
N = (500 - 2x1)/(4x0.03/2π)(720/2)
N = 1500 RPM

2. Calculate back emf (Eb) from back emf equation:
Eb = (PΦZN)/60A
Eb = (4x0.03x720x1500)/60
Eb = 486V

Therefore, the correct answer is option (D) 486V.
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A 4-pole 500V shunt motor has 720 wave connected conductors on its armature. The fullload armature current is 60A and flux per pole is 0.03 Wb. The armature resistance is 0.2 Wand the contact drop per brush is 1V. What is the back emf ?a)490Vb)460Vc)445Vd)486VCorrect answer is option 'D'. Can you explain this answer?
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