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The zero magnetic moment of octahedral 
is due to:
is due to:a) Low spin 
Ni(IV) complex
Ni(IV) complexb) Low spin 
Ni(II) complex
Ni(II) complexc) High spin Ni(II) complex
Ni(II) complexd) High spin Ni(IV) complex
Ni(IV) complex The correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The zero magnetic moment of octahedralis due to:a) Low spinNi(IV) comp...
Oxidation state of Ni in [NiF6]2- :
x − 6 = −2
x = + 4
In +4 oxidation state, fluoride also behaves as a strong field ligand.
⇒ low spin d6 Ni(IV) complex.
⇒ unpaired electrons = 0.
⇒ zero magnetic moment.
x − 6 = −2
x = + 4
In +4 oxidation state, fluoride also behaves as a strong field ligand.
⇒ low spin d6 Ni(IV) complex.
⇒ unpaired electrons = 0.
⇒ zero magnetic moment.
Most Upvoted Answer
The zero magnetic moment of octahedralis due to:a) Low spinNi(IV) comp...
Explanation:
In order to understand why the zero magnetic moment of octahedral K2NiF6 is due to a low spin d6 Ni(IV) complex, we need to analyze the electronic configuration and magnetic properties of the complex.
1. Electronic configuration of Ni(IV) in octahedral K2NiF6:
- The atomic number of Ni is 28, which means it has 28 electrons.
- In K2NiF6, each K+ ion donates one electron, resulting in a total of 2 electrons.
- Each F- ion accepts one electron, resulting in a total of 6 electrons.
- Therefore, the Ni(IV) ion has a total of 28 - 2 - 6 = 20 electrons.
2. Determining the electronic configuration:
- The electronic configuration of Ni(IV) is [Ar] 3d6.
- In an octahedral complex, the d-orbitals split into two sets of energy levels: the lower energy t2g set (dxy, dyz, dzx) and the higher energy eg set (dz2, dx2-y2).
- The electron configuration of Ni(IV) in an octahedral complex can be represented as t2g6 eg0.
3. Determining the spin state:
- The spin state of a complex is dependent on the number of unpaired electrons.
- In a low spin complex, electrons are paired up in the t2g orbitals before populating the eg orbitals.
- In a high spin complex, electrons are first placed in the eg orbitals, leading to unpaired electrons in the t2g orbitals.
- In the case of K2NiF6, since there are 6 electrons in the t2g orbitals, all the orbitals are filled, resulting in a low spin state with zero unpaired electrons.
4. Magnetic moment:
- The magnetic moment of a complex is a measure of the strength of its magnetic field.
- When there are unpaired electrons, the complex has a non-zero magnetic moment due to the presence of magnetic interactions between the electrons.
- In the case of K2NiF6, since there are zero unpaired electrons, the magnetic interactions are canceled out, leading to a zero magnetic moment.
Conclusion:
The zero magnetic moment of octahedral K2NiF6 is due to the low spin d6 Ni(IV) complex, where all the electrons are paired up in the t2g orbitals, resulting in a cancellation of magnetic interactions and a zero magnetic moment.
In order to understand why the zero magnetic moment of octahedral K2NiF6 is due to a low spin d6 Ni(IV) complex, we need to analyze the electronic configuration and magnetic properties of the complex.
1. Electronic configuration of Ni(IV) in octahedral K2NiF6:
- The atomic number of Ni is 28, which means it has 28 electrons.
- In K2NiF6, each K+ ion donates one electron, resulting in a total of 2 electrons.
- Each F- ion accepts one electron, resulting in a total of 6 electrons.
- Therefore, the Ni(IV) ion has a total of 28 - 2 - 6 = 20 electrons.
2. Determining the electronic configuration:
- The electronic configuration of Ni(IV) is [Ar] 3d6.
- In an octahedral complex, the d-orbitals split into two sets of energy levels: the lower energy t2g set (dxy, dyz, dzx) and the higher energy eg set (dz2, dx2-y2).
- The electron configuration of Ni(IV) in an octahedral complex can be represented as t2g6 eg0.
3. Determining the spin state:
- The spin state of a complex is dependent on the number of unpaired electrons.
- In a low spin complex, electrons are paired up in the t2g orbitals before populating the eg orbitals.
- In a high spin complex, electrons are first placed in the eg orbitals, leading to unpaired electrons in the t2g orbitals.
- In the case of K2NiF6, since there are 6 electrons in the t2g orbitals, all the orbitals are filled, resulting in a low spin state with zero unpaired electrons.
4. Magnetic moment:
- The magnetic moment of a complex is a measure of the strength of its magnetic field.
- When there are unpaired electrons, the complex has a non-zero magnetic moment due to the presence of magnetic interactions between the electrons.
- In the case of K2NiF6, since there are zero unpaired electrons, the magnetic interactions are canceled out, leading to a zero magnetic moment.
Conclusion:
The zero magnetic moment of octahedral K2NiF6 is due to the low spin d6 Ni(IV) complex, where all the electrons are paired up in the t2g orbitals, resulting in a cancellation of magnetic interactions and a zero magnetic moment.
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The zero magnetic moment of octahedralis due to:a) Low spinNi(IV) comp...
A and d both correct ..
+4 oxidation state me sabhi ligand strong behave karte hai..
+4 oxidation state me sabhi ligand strong behave karte hai..
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The zero magnetic moment of octahedralis due to:a) Low spinNi(IV) complexb) Low spinNi(II) complexc) High spinNi(II) complexd) High spinNi(IV) complex The correct answer is option 'A'. Can you explain this answer?
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