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The zero magnetic moment of octahedral K2NiF6 is due to:
- a)Low spin d6 Ni(IV) complex
- b)Low spin d8 Ni(II) complex
- c)High spin d8 Ni(II) complex
- d)High spin d6 Ni(IV) complex
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The zero magnetic moment of octahedral K2NiF6 is due to:a)Low spin d6 ...
Explanation:
The zero magnetic moment of octahedral K2NiF6 is due to low spin d6 Ni(IV) complex. This can be explained as follows:
1. Octahedral K2NiF6: The given compound K2NiF6 has an octahedral geometry with two potassium ions (K+) and one nickel ion (Ni2+) surrounded by six fluoride ions (F−) in an octahedral arrangement.
2. Magnetic moment: The magnetic moment of a compound is a measure of the strength and orientation of its magnetic field. It is expressed in terms of the number of Bohr magnetons (μB) per molecule.
3. Low spin d6 Ni(IV) complex: The nickel ion (Ni2+) in K2NiF6 has a d6 electronic configuration with four electrons in the t2g orbitals and two electrons in the eg orbitals. In the low spin state, the electrons fill the t2g orbitals before the eg orbitals, resulting in a configuration of dxy2, dyz2, dzx2, dx2-y2, with no unpaired electrons. This leads to a magnetic moment of zero.
4. High spin d8 Ni(II) complex: If the nickel ion (Ni2+) had a d8 electronic configuration, with six electrons in the t2g orbitals and two electrons in the eg orbitals, and was in the high spin state, the electrons would fill both the t2g and eg orbitals, resulting in a configuration of dxy2, dyz2, dzx2, dx2-y2, dxz, and dyz, with two unpaired electrons. This would lead to a non-zero magnetic moment.
Therefore, the zero magnetic moment of octahedral K2NiF6 is due to the low spin d6 Ni(IV) complex.
The zero magnetic moment of octahedral K2NiF6 is due to low spin d6 Ni(IV) complex. This can be explained as follows:
1. Octahedral K2NiF6: The given compound K2NiF6 has an octahedral geometry with two potassium ions (K+) and one nickel ion (Ni2+) surrounded by six fluoride ions (F−) in an octahedral arrangement.
2. Magnetic moment: The magnetic moment of a compound is a measure of the strength and orientation of its magnetic field. It is expressed in terms of the number of Bohr magnetons (μB) per molecule.
3. Low spin d6 Ni(IV) complex: The nickel ion (Ni2+) in K2NiF6 has a d6 electronic configuration with four electrons in the t2g orbitals and two electrons in the eg orbitals. In the low spin state, the electrons fill the t2g orbitals before the eg orbitals, resulting in a configuration of dxy2, dyz2, dzx2, dx2-y2, with no unpaired electrons. This leads to a magnetic moment of zero.
4. High spin d8 Ni(II) complex: If the nickel ion (Ni2+) had a d8 electronic configuration, with six electrons in the t2g orbitals and two electrons in the eg orbitals, and was in the high spin state, the electrons would fill both the t2g and eg orbitals, resulting in a configuration of dxy2, dyz2, dzx2, dx2-y2, dxz, and dyz, with two unpaired electrons. This would lead to a non-zero magnetic moment.
Therefore, the zero magnetic moment of octahedral K2NiF6 is due to the low spin d6 Ni(IV) complex.
Community Answer
The zero magnetic moment of octahedral K2NiF6 is due to:a)Low spin d6 ...
With higher oxidation state F behave like strong field ligend, so option A correct
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The zero magnetic moment of octahedral K2NiF6 is due to:a)Low spin d6 Ni(IV) complexb)Low spin d8 Ni(II) complexc)High spin d8 Ni(II) complexd)High spin d6 Ni(IV) complexCorrect answer is option 'A'. Can you explain this answer?
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