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If the curved surface of right circular cylinder inscribed in a sphere of radius r is maximum show the height of the cylinder is√2r?
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If the curved surface of right circular cylinder inscribed in a sphere...
Explanation:

We are given a right circular cylinder inscribed in a sphere of radius r. We need to find the height of the cylinder such that the curved surface area of the cylinder is maximum.

Let's consider a cross-section of the cylinder and the sphere that contains it.



Step 1: Deriving the Formula for Curved Surface Area of Cylinder

The curved surface area of the cylinder is given by:

C.S.A. = 2πrh

where r is the radius of the cylinder and h is the height of the cylinder.

Step 2: Deriving the Formula for Radius of Cylinder

The radius of the cylinder can be found using the Pythagorean theorem as follows:

r^2 + h^2 = (2r)^2

Simplifying the above equation, we get:

h^2 = 3r^2

Therefore, the radius of the cylinder is:

r = h/√3

Step 3: Deriving the Formula for Curved Surface Area of Cylinder in terms of h

Substituting the value of r in the formula for C.S.A., we get:

C.S.A. = 2πrh = 2π(h/√3)h = (2π/√3)h^2

Step 4: Finding the Maximum Value of C.S.A.

To find the maximum value of the curved surface area, we differentiate the formula for C.S.A. with respect to h and equate it to zero.

d/dh [(2π/√3)h^2] = (4π/√3)h = 0

Solving the above equation, we get:

h = √2r

Therefore, the height of the cylinder that maximizes the curved surface area is √2r.

Conclusion:

Hence, we have shown that the height of the cylinder is √2r when the curved surface area of the cylinder is maximum.
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If the curved surface of right circular cylinder inscribed in a sphere of radius r is maximum show the height of the cylinder is√2r?
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