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An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2 k(x – X)2. A particle of mass m comes from right  with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)
  • a)
    2/3
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
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An oscillator of mass M is at rest in the equilibrium position in a po...
In first collision mu momentum will be imparted to system. In second collision when momentum of (M + m) is in opposite direction mu momentum of particle will make its momentum zero. on 13th collision

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An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2k(x – X)2. A particle ofmass m comes from right with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)a)2/3b)c)d)Correct answer is option 'B'. Can you explain this answer?
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An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2k(x – X)2. A particle ofmass m comes from right with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)a)2/3b)c)d)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2k(x – X)2. A particle ofmass m comes from right with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)a)2/3b)c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An oscillator of mass M is at rest in the equilibrium position in a potential V = 1/2k(x – X)2. A particle ofmass m comes from right with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)a)2/3b)c)d)Correct answer is option 'B'. Can you explain this answer?.
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