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In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :
- a)sp3d, trigonal bipyramidal
- b)d2sp3, octahedral
- c)dsp2, square planar
- d)sp3, tetrahedral
Correct answer is option 'C'. Can you explain this answer?
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In Wilkinson's catalyst, the hybridization of central metal ion an...
Wilkinson catalyst
[RhCl(PPh3)3]
[RhCl(PPh3)3]
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In Wilkinson's catalyst, the hybridization of central metal ion an...
Explanation:
Wilkinson's catalyst is a coordination complex with the chemical formula [RhCl(PPh3)3]. It consists of a central rhodium ion (Rh) surrounded by three triphenylphosphine ligands (PPh3) and one chloride ion (Cl-).
Hybridization of central metal ion:
The central rhodium ion in Wilkinson's catalyst is in dsp2 hybridization. This means that the d orbital and two p orbitals of the central metal ion are involved in hybridization. The three triphenylphosphine ligands donate their lone pairs of electrons to the central metal ion, resulting in the formation of three sigma bonds. These sigma bonds are formed by the overlap of the hybrid orbitals of the central metal ion with the orbitals of the ligands.
Shape of the complex:
The shape of Wilkinson's catalyst is square planar. It is determined by the arrangement of the ligands around the central metal ion. In this case, the three triphenylphosphine ligands are arranged in a trigonal plane around the central metal ion, and the chloride ion is located above and below this plane. This arrangement gives the complex a square planar shape.
Summary:
- The central rhodium ion in Wilkinson's catalyst is in dsp2 hybridization.
- The shape of the complex is square planar.
- The three triphenylphosphine ligands are arranged in a trigonal plane around the central metal ion, and the chloride ion is located above and below this plane.
Wilkinson's catalyst is a coordination complex with the chemical formula [RhCl(PPh3)3]. It consists of a central rhodium ion (Rh) surrounded by three triphenylphosphine ligands (PPh3) and one chloride ion (Cl-).
Hybridization of central metal ion:
The central rhodium ion in Wilkinson's catalyst is in dsp2 hybridization. This means that the d orbital and two p orbitals of the central metal ion are involved in hybridization. The three triphenylphosphine ligands donate their lone pairs of electrons to the central metal ion, resulting in the formation of three sigma bonds. These sigma bonds are formed by the overlap of the hybrid orbitals of the central metal ion with the orbitals of the ligands.
Shape of the complex:
The shape of Wilkinson's catalyst is square planar. It is determined by the arrangement of the ligands around the central metal ion. In this case, the three triphenylphosphine ligands are arranged in a trigonal plane around the central metal ion, and the chloride ion is located above and below this plane. This arrangement gives the complex a square planar shape.
Summary:
- The central rhodium ion in Wilkinson's catalyst is in dsp2 hybridization.
- The shape of the complex is square planar.
- The three triphenylphosphine ligands are arranged in a trigonal plane around the central metal ion, and the chloride ion is located above and below this plane.
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In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer?
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In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer?.
In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :a)sp3d, trigonal bipyramidalb)d2sp3, octahedralc)dsp2, square planard)sp3, tetrahedralCorrect answer is option 'C'. Can you explain this answer?.
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