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Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2 for the mixture then the value of n is
- a)1
- b)3
- c)2
- d)3/2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/...
Let's solve the problem step by step:
Given:
- 2 moles of helium
- n moles of hydrogen
We need to find the value of n such that Cp/Cv = 3/2 for the mixture.
First, let's calculate the total number of moles in the mixture:
Total moles = moles of helium + moles of hydrogen
= 2 + n
= n + 2
Next, let's calculate the heat capacities for the mixture:
Cp = Cp(helium) + Cp(hydrogen)
Cv = Cv(helium) + Cv(hydrogen)
For helium, the ratio of Cp/Cv is given to be 3/2. Therefore, we can write:
Cp(helium)/Cv(helium) = 3/2
Similarly, for hydrogen, let's assume the ratio of Cp/Cv is x. Therefore, we can write:
Cp(hydrogen)/Cv(hydrogen) = x
Now, let's substitute the values of Cp and Cv for the mixture:
Cp/Cv = (Cp(helium) + Cp(hydrogen))/(Cv(helium) + Cv(hydrogen))
= (3/2 + x)/(1 + x)
According to the given condition, Cp/Cv = 3/2. Therefore, we can write:
(3/2)/(1) = (3/2 + x)/(1 + x)
Cross multiplying, we get:
3(1 + x) = 2(3/2 + x)
3 + 3x = 3 + 2x
Simplifying further, we find:
x = 3
Hence, the value of n is 3.
Therefore, the correct answer is option 'C'.
Given:
- 2 moles of helium
- n moles of hydrogen
We need to find the value of n such that Cp/Cv = 3/2 for the mixture.
First, let's calculate the total number of moles in the mixture:
Total moles = moles of helium + moles of hydrogen
= 2 + n
= n + 2
Next, let's calculate the heat capacities for the mixture:
Cp = Cp(helium) + Cp(hydrogen)
Cv = Cv(helium) + Cv(hydrogen)
For helium, the ratio of Cp/Cv is given to be 3/2. Therefore, we can write:
Cp(helium)/Cv(helium) = 3/2
Similarly, for hydrogen, let's assume the ratio of Cp/Cv is x. Therefore, we can write:
Cp(hydrogen)/Cv(hydrogen) = x
Now, let's substitute the values of Cp and Cv for the mixture:
Cp/Cv = (Cp(helium) + Cp(hydrogen))/(Cv(helium) + Cv(hydrogen))
= (3/2 + x)/(1 + x)
According to the given condition, Cp/Cv = 3/2. Therefore, we can write:
(3/2)/(1) = (3/2 + x)/(1 + x)
Cross multiplying, we get:
3(1 + x) = 2(3/2 + x)
3 + 3x = 3 + 2x
Simplifying further, we find:
x = 3
Hence, the value of n is 3.
Therefore, the correct answer is option 'C'.
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Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer?.
Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of helium are mixed with an moles of hydrogen. If Cp/Cv = 3/2for the mixture then the value of n isa)1b)3c)2d)3/2Correct answer is option 'C'. Can you explain this answer?.
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