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A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :
- a)22.4V
- b)7V
- c)11.2V
- d)28V
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A carrier wave of peak voltage 14V is used for transmitting a message ...
To determine the peak voltage required to achieve a modulation index of 80%, we first need to understand what modulation index represents in the context of amplitude modulation (AM).
Modulation index, also known as the modulation depth, is the ratio of the peak amplitude of the modulating signal to the peak amplitude of the carrier signal. It indicates the extent to which the carrier signal is varied by the modulating signal.
In this case, the modulation index is given as 80%. Mathematically, modulation index (m) is calculated as:
m = (V_m/V_c) * 100
where V_m is the peak amplitude of the modulating signal and V_c is the peak amplitude of the carrier signal.
Now let's solve the given problem step by step:
Step 1: Convert the given modulation index from percentage to decimal form.
Modulation index (m) = 80% = 0.80
Step 2: Rearrange the formula to solve for V_m.
V_m = (m * V_c) / 100
Step 3: Substitute the values into the formula.
V_m = (0.80 * 14V) / 100
V_m = 11.2V
Therefore, the peak voltage of the modulating signal required to achieve a modulation index of 80% is 11.2V. Hence, the correct answer is option C.
Modulation index, also known as the modulation depth, is the ratio of the peak amplitude of the modulating signal to the peak amplitude of the carrier signal. It indicates the extent to which the carrier signal is varied by the modulating signal.
In this case, the modulation index is given as 80%. Mathematically, modulation index (m) is calculated as:
m = (V_m/V_c) * 100
where V_m is the peak amplitude of the modulating signal and V_c is the peak amplitude of the carrier signal.
Now let's solve the given problem step by step:
Step 1: Convert the given modulation index from percentage to decimal form.
Modulation index (m) = 80% = 0.80
Step 2: Rearrange the formula to solve for V_m.
V_m = (m * V_c) / 100
Step 3: Substitute the values into the formula.
V_m = (0.80 * 14V) / 100
V_m = 11.2V
Therefore, the peak voltage of the modulating signal required to achieve a modulation index of 80% is 11.2V. Hence, the correct answer is option C.
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A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer?.
A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A carrier wave of peak voltage 14V is used for transmitting a message signal given to achieve a modulation index of 80% will be :a)22.4Vb)7Vc)11.2Vd)28VCorrect answer is option 'C'. Can you explain this answer?.
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