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Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12, then the number of children in each family is :
- a)6
- b)5
- c)3
- d)4
Correct answer is option 'B'. Can you explain this answer?
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Two different families A and B are blessed with equal number of childr...
Let n number of children are there in each family
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Two different families A and B are blessed with equal number of childr...
Explanation:
Given:
- Two families A and B have an equal number of children.
- There are 3 tickets to be distributed among the children of these families.
- The probability that all the tickets go to the children of family B is 1/12.
Let:
- Let the number of children in each family be x.
Calculating the Total Number of Ways:
- The total number of ways to distribute 3 tickets among x children from Family A and x children from Family B is C(2x,3) = (2x)! / [3!(2x-3)!].
- Since the total number of ways is given as C(2x,3), it implies that the total number of children in both families is 6 (2x=6).
Calculating the Number of Ways for All Tickets to Go to Family B:
- The number of ways in which all 3 tickets can go to the children of Family B is C(x,3) = x! / [3!(x-3)!].
- Given that the probability of this event is 1/12, it implies that the number of ways for all tickets to go to Family B is equal to 1/12 of the total number of ways.
Solving for x:
- Setting up the equation x! / [3!(x-3)!] = 1/12 and simplifying, we get x(x-1)(x-2) = 6.
- Solving this equation, we find that x=5.
Therefore, each family has 5 children. Hence, the correct answer is option 'B'.
Given:
- Two families A and B have an equal number of children.
- There are 3 tickets to be distributed among the children of these families.
- The probability that all the tickets go to the children of family B is 1/12.
Let:
- Let the number of children in each family be x.
Calculating the Total Number of Ways:
- The total number of ways to distribute 3 tickets among x children from Family A and x children from Family B is C(2x,3) = (2x)! / [3!(2x-3)!].
- Since the total number of ways is given as C(2x,3), it implies that the total number of children in both families is 6 (2x=6).
Calculating the Number of Ways for All Tickets to Go to Family B:
- The number of ways in which all 3 tickets can go to the children of Family B is C(x,3) = x! / [3!(x-3)!].
- Given that the probability of this event is 1/12, it implies that the number of ways for all tickets to go to Family B is equal to 1/12 of the total number of ways.
Solving for x:
- Setting up the equation x! / [3!(x-3)!] = 1/12 and simplifying, we get x(x-1)(x-2) = 6.
- Solving this equation, we find that x=5.
Therefore, each family has 5 children. Hence, the correct answer is option 'B'.
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Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer?
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Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer?.
Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two different families A and B are blessed with equal number of children. There are 3 tickests to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 1/12,then the number of children in eachfamily is :a)6b)5c)3d)4Correct answer is option 'B'. Can you explain this answer?.
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