Question Description
Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer?.

Solutions for Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Let P be a point on the parabola, x2 = 4y. If the distance of P from the centre of the circle, x2 + y2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :a)x + y + 1 = 0b)x + 4y – 2 = 0c)x + 2y = 0d)x – y + 3 = 0Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.