The total number of subsets of a finite set A has 56 more elements, th...
Let sets A and B have m and n elements, respectively,
Then 2m - 2n = 56 (According to question)
implies2n(2m-n - 1)
= 8 x 7 = (2)3 x 7 = 23(23- l )
On comparing implies n = 3
and m-n = 3
implies m = 6 and n = 3
Number of subsets of A = 23 + 56 = 64 = 26
Hence,Number of elements of in A = 6
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The total number of subsets of a finite set A has 56 more elements, th...
To solve this problem, we need to determine the number of elements in set A that satisfies the given condition.
Let's assume the number of elements in set A is 'n'.
The total number of subsets of a set with 'n' elements can be calculated using the formula 2^n. Similarly, the total number of subsets of set B would be 2^(n-3) since it has 3 fewer elements than set A.
According to the given condition, the total number of subsets of set A is 56 more than the total number of subsets of set B.
So, we can set up the equation as follows:
2^n = 2^(n-3) + 56
To simplify the equation, we can rewrite it as:
2^n = 2^n * 2^(-3) + 56
Since 2^(-3) is equal to 1/2^3 = 1/8, we can substitute it back into the equation:
2^n = 2^n/8 + 56
Next, we can multiply both sides of the equation by 8 to eliminate the fraction:
8 * 2^n = 2^n + 448
Now, we can subtract 2^n from both sides of the equation:
7 * 2^n = 448
Dividing both sides of the equation by 7:
2^n = 64
Now, we can determine the value of 'n' by finding the exponent that gives us 64.
We know that 2^6 = 64, so 'n' must be 6.
Therefore, the number of elements in set A is 6, which corresponds to option 'B'.