A can work twice as fast as B. If they work together complete a work i...
Problem Analysis:
Let's assume that B takes x days to complete the work alone. Therefore, A will take half the time i.e. x/2 days to complete the same work alone.
When they work together, their combined efficiency will be the sum of their individual efficiencies. So, the equation can be formed as:
1/x + 2/x = 1/12
Solving this equation, we will get the value of x which is the number of days B will take to complete the work alone.
Solution:
Given that A can work twice as fast as B. So, if B takes x days to complete the work alone, then A will take x/2 days to complete the same work alone.
When they work together, their combined efficiency will be:
Efficiency of A + Efficiency of B = 1/12 (as they complete the work in 12 days when working together)
Substituting the individual efficiencies in the above equation, we get:
1/(x/2) + 1/x = 1/12
2/x + 1/x = 1/12
3/x = 1/12
x = 36
Therefore, B alone will complete the work in 36 days.
Answer:
B alone will complete the work in 36 days.