12 men can finish our work in 10 days how many more man are needed to ...
Given Information:
- 12 men can finish a work in 10 days
Calculating Work Rate:
To find out how many more men are needed to complete the work in six days, we need to calculate the work rate of the 12 men.
- Let's assume that the total work is denoted by "W".
- Since 12 men can complete the work in 10 days, the work rate of the 12 men is given by W/10.
Calculating the Total Work:
- The total work can be calculated by multiplying the work rate of the 12 men by the number of days it takes them to complete the work.
- So, the total work is equal to (W/10) x 10 = W.
Calculating the Work Rate for 6 Days:
- To calculate the work rate for 6 days, we divide the total work by the number of days.
- So, the work rate for 6 days is given by W/6.
Calculating the Number of Men Required:
- Let's assume that the number of additional men required is denoted by "x".
- The total work done by the additional men in 6 days is given by (W/6) x 6 = W.
- Since the work rate of each man is W/6, the total work done by x men in 6 days is given by (W/6) x x.
Equating the Work Done:
- The total work done by the 12 men and the additional x men should be equal to the total work.
- So, we have the equation (W/10) x 10 + (W/6) x x = W.
Simplifying the Equation:
- Simplifying the equation, we get 12W/10 + xW/6 = W.
- Multiplying both sides of the equation by 30 to eliminate the denominators, we get 12W x 3 + xW x 5 = 30W.
- Simplifying further, we get 36W + 5xW = 30W.
- Subtracting 30W from both sides, we get 6W + 5xW = 0.
Solving for x:
- Combining like terms, we have 11xW = -6W.
- Dividing both sides by -6W, we get 11x = -6.
- Dividing both sides by 11, we get x = -6/11.
Conclusion:
- Since the number of men cannot be negative, we cannot complete the work in 6 days by adding more men.
- In fact, we would need to remove some men to complete the work in a shorter time.
- Therefore, we cannot determine the exact number of additional men required to complete the work in six days.