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A snail tries to climb a 22 metres wall. During a day, the snail climbs 6 metres up and slips 2 metres down at night. How many days shall it take to reach the top?
  • a)
    5
  • b)
    6
  • c)
    4
  • d)
    3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A snail tries to climb a 22 metres wall. During a day, the snail climb...
During one day (including day and night) the snail climbs: (6 - 2) = 4 metres.
Let the number of days it would take to climb the wall up be x.
Distance traveled on last day (the moment the reaches top he will be able to cross it, thus slipping is not considered) + Distance traveled on remaining days = Wall height
6 + 4 (x − 1) = 22
4 (x − 1) = 22 − 6 = 16
x = 20/4 = 5.
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Most Upvoted Answer
A snail tries to climb a 22 metres wall. During a day, the snail climb...
Solution:

To climb a 22 metres wall, the snail will need to climb 22 metres.

During the day, the snail climbs 6 metres up and slips 2 metres down at night. Therefore, the snail climbs 6-2=4 metres every day.

To climb 22 metres, the snail will need 22/4=5.5 days.

Since the snail cannot climb half a day, it will take 6 days to reach the top.

Therefore, the correct answer is option 'A', which is 5 days.

Alternatively, we can use the following formula to calculate the number of days required:

Number of days = Ceiling(Height climbed / Daily progress)

Where Ceiling function rounds up the value to the nearest integer.

Using this formula, we get:

Number of days = Ceiling(22 / 4) = Ceiling(5.5) = 6

Therefore, the correct answer is option 'A', which is 5 days.
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A snail tries to climb a 22 metres wall. During a day, the snail climbs 6 metres up and slips 2 metres down at night. How many days shall it take to reach the top?a)5b)6c)4d)3Correct answer is option 'A'. Can you explain this answer?
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