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When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:
- a)0.1
- b)0.5
- c)1.0
- d)2.0
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
When an electric current is passed through acidified water, 112 mL of ...
at NTP 1 mol = 22. 4 l
112 ml H2 ⇒
⇒ 1/200 mol of H2
H2O → H2 + 1/2 O2
2H− + 2e− → H2
1 mol of H2 required 2 mole e̅
1/200 mol of H2 require 2/200 = 1/100 mol of e̅
1/100 mol of e̅ = 1/100 × 6.022 × 1023e̅ × 1.6 × 10−19
112 ml H2 ⇒
⇒ 1/200 mol of H2
H2O → H2 + 1/2 O2
2H− + 2e− → H2
1 mol of H2 required 2 mole e̅
1/200 mol of H2 require 2/200 = 1/100 mol of e̅
1/100 mol of e̅ = 1/100 × 6.022 × 1023e̅ × 1.6 × 10−19
Most Upvoted Answer
When an electric current is passed through acidified water, 112 mL of ...
Given:
- Volume of hydrogen gas collected at cathode = 112 mL
- Time taken = 965 seconds
- Normal temperature and pressure (N.T.P.)
To find:
The current passed through the acidified water in amperes.
Formula used:
The Faraday's law of electrolysis states that the amount of substance produced at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.
The equation for the Faraday's law of electrolysis is given by:
Q = I * t
Where:
Q = quantity of electricity passed (in coulombs)
I = current (in amperes)
t = time (in seconds)
The quantity of electricity passed can be calculated using the formula:
Q = n * F
Where:
n = number of moles of hydrogen gas produced
F = Faraday's constant (96485 C/mol)
The number of moles of hydrogen gas produced can be calculated using the ideal gas equation:
n = V / Vm
Where:
V = volume of hydrogen gas collected (in mL)
Vm = molar volume of gas at N.T.P. (22.4 L/mol)
Solution:
1. Convert the volume of hydrogen gas collected to liters:
112 mL = 112/1000 = 0.112 L
2. Calculate the number of moles of hydrogen gas produced:
n = V / Vm = 0.112 / 22.4 = 0.005 mol
3. Calculate the quantity of electricity passed:
Q = n * F = 0.005 * 96485 = 482.425 C
4. Substitute the values into the equation Q = I * t to find the current:
482.425 = I * 965
I = 482.425 / 965 = 0.5 A
Answer:
The current passed through the acidified water is 0.5 amperes. Therefore, the correct answer is option 'b) 0.5'.
- Volume of hydrogen gas collected at cathode = 112 mL
- Time taken = 965 seconds
- Normal temperature and pressure (N.T.P.)
To find:
The current passed through the acidified water in amperes.
Formula used:
The Faraday's law of electrolysis states that the amount of substance produced at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.
The equation for the Faraday's law of electrolysis is given by:
Q = I * t
Where:
Q = quantity of electricity passed (in coulombs)
I = current (in amperes)
t = time (in seconds)
The quantity of electricity passed can be calculated using the formula:
Q = n * F
Where:
n = number of moles of hydrogen gas produced
F = Faraday's constant (96485 C/mol)
The number of moles of hydrogen gas produced can be calculated using the ideal gas equation:
n = V / Vm
Where:
V = volume of hydrogen gas collected (in mL)
Vm = molar volume of gas at N.T.P. (22.4 L/mol)
Solution:
1. Convert the volume of hydrogen gas collected to liters:
112 mL = 112/1000 = 0.112 L
2. Calculate the number of moles of hydrogen gas produced:
n = V / Vm = 0.112 / 22.4 = 0.005 mol
3. Calculate the quantity of electricity passed:
Q = n * F = 0.005 * 96485 = 482.425 C
4. Substitute the values into the equation Q = I * t to find the current:
482.425 = I * 965
I = 482.425 / 965 = 0.5 A
Answer:
The current passed through the acidified water is 0.5 amperes. Therefore, the correct answer is option 'b) 0.5'.
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When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer?
Question Description
When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer?.
When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer?.
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When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P. was collected at the cathode in 965 seconds. The current passed, in ampere, is:a)0.1b)0.5c)1.0d)2.0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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