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The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:
- a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)
- b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3
- c)PPh3, [Ph3CH3]I and [Ph3P=CH2]
- d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)Li
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of t...
To determine the products X, Y, and Z in the given reaction sequence, let's analyze each step:
1. Reaction of PCl3 with PhLi in a 1:3 molar ratio:
- PCl3 (phosphorus trichloride) reacts with PhLi (phenyllithium) to form a complex intermediate.
- The reaction can be represented as:
PCl3 + 3PhLi → intermediate (X)
2. Further treatment of X with CH3I:
- The intermediate X reacts with CH3I (methyl iodide) to form a new product Y.
- This reaction is a nucleophilic substitution where the iodide ion (I-) from CH3I replaces one of the Ph groups in the intermediate.
- The reaction can be represented as:
Intermediate (X) + CH3I → Y
3. Reaction of Y with n-BuLi:
- The product Y reacts with n-BuLi (n-butyllithium) to form a new product Z.
- This reaction is again a nucleophilic substitution where the n-Bu group from n-BuLi replaces one of the Ph groups in Y.
- The reaction can be represented as:
Y + n-BuLi → Z
Based on the above analysis, the correct answer is option C:
- Product X is PPh3 (triphenylphosphine), which is formed from the reaction of PCl3 and PhLi.
- Product Y is [Ph3CH3]I (triphenylmethyl iodide), which is formed from the further treatment of X with CH3I.
- Product Z is [Ph3P=CH2] (triphenylphosphine methylene), which is formed from the reaction of Y with n-BuLi.
Summary:
- X is PPh3 (triphenylphosphine).
- Y is [Ph3CH3]I (triphenylmethyl iodide).
- Z is [Ph3P=CH2] (triphenylphosphine methylene).
1. Reaction of PCl3 with PhLi in a 1:3 molar ratio:
- PCl3 (phosphorus trichloride) reacts with PhLi (phenyllithium) to form a complex intermediate.
- The reaction can be represented as:
PCl3 + 3PhLi → intermediate (X)
2. Further treatment of X with CH3I:
- The intermediate X reacts with CH3I (methyl iodide) to form a new product Y.
- This reaction is a nucleophilic substitution where the iodide ion (I-) from CH3I replaces one of the Ph groups in the intermediate.
- The reaction can be represented as:
Intermediate (X) + CH3I → Y
3. Reaction of Y with n-BuLi:
- The product Y reacts with n-BuLi (n-butyllithium) to form a new product Z.
- This reaction is again a nucleophilic substitution where the n-Bu group from n-BuLi replaces one of the Ph groups in Y.
- The reaction can be represented as:
Y + n-BuLi → Z
Based on the above analysis, the correct answer is option C:
- Product X is PPh3 (triphenylphosphine), which is formed from the reaction of PCl3 and PhLi.
- Product Y is [Ph3CH3]I (triphenylmethyl iodide), which is formed from the further treatment of X with CH3I.
- Product Z is [Ph3P=CH2] (triphenylphosphine methylene), which is formed from the reaction of Y with n-BuLi.
Summary:
- X is PPh3 (triphenylphosphine).
- Y is [Ph3CH3]I (triphenylmethyl iodide).
- Z is [Ph3P=CH2] (triphenylphosphine methylene).
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The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer?
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The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer?.
The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Here you can find the meaning of The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The reaction of PCl3 with PhLi in 1:3 molar ratio yields X as one of the products, which on further treatment with CH3I gives Y. The reaction of Y with n-BuLi gives product Z. The products X, Y and Z are resp:a)[PPh4]Cl, [Ph2P=CH2] and Ph2P(n-Bu)b)PPh3, [Ph3PI]CH3 and Ph2P(n-Bu)3c)PPh3, [Ph3CH3]I and [Ph3P=CH2]d)[PPh4]Cl, [Ph2P=CH2] and Ph3P(n-Bu)LiCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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