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The inter-planar spacing for (111) plane in a cubic unit cell of side length of 4.2Å is (in Å) is
(rounded up to first decimal place)
(rounded up to first decimal place)
Correct answer is between '2.4,2.5'. Can you explain this answer?
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The inter-planar spacing for (111) plane in a cubic unit cell of side ...
To calculate the interplanar spacing for the (111) plane in a cubic unit cell, we can use the formula:
d = a / √(h^2 + k^2 + l^2)
Where:
d is the interplanar spacing,
a is the side length of the cubic unit cell,
h, k, and l are the Miller indices of the plane.
For the (111) plane, h = 1, k = 1, and l = 1.
Given that the side length of the cubic unit cell is 4.2, we can substitute these values into the formula:
d = 4.2 / √(1^2 + 1^2 + 1^2)
= 4.2 / √(3)
≈ 4.2 / 1.732
≈ 2.426
Therefore, the interplanar spacing for the (111) plane in a cubic unit cell with a side length of 4.2 is approximately 2.426.
d = a / √(h^2 + k^2 + l^2)
Where:
d is the interplanar spacing,
a is the side length of the cubic unit cell,
h, k, and l are the Miller indices of the plane.
For the (111) plane, h = 1, k = 1, and l = 1.
Given that the side length of the cubic unit cell is 4.2, we can substitute these values into the formula:
d = 4.2 / √(1^2 + 1^2 + 1^2)
= 4.2 / √(3)
≈ 4.2 / 1.732
≈ 2.426
Therefore, the interplanar spacing for the (111) plane in a cubic unit cell with a side length of 4.2 is approximately 2.426.
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