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The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared
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the Chemistry exam syllabus. Information about The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam.
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The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The molar conductivity of 0.009 M aqueous solution of a weak acid (HA) is0.005 Sm2mol-1and the limiting molar conductivity of HA is0.005 Sm2mol-1at 298 K. Assuming activity coefficients to be unity, the acid dissociation constant (Ka)of HA at this temperature isa)1×10−4b)0.1c)9×10−4d)1.1×10−5Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.