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A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:
- a)12000 symbol/s
- b)1800 symbol/s
- c)3000 symbol/s
- d)6000 symbol/s
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is con...
The symbol rate required for error tree transmission, i.e. nyquist sampling rate is
= 6000 symbols/sec
= 6000 symbols/sec
Most Upvoted Answer
A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is con...
Calculation of Signal-to-Noise Ratio (SNR):
The signal-to-noise ratio (SNR) can be calculated using the following formula:
SNR = 10log10 (Psignal/Pnoise)
where Psignal is the signal power and Pnoise is the noise power.
Given that the SNR of the telephone channel is 30dB, we can use the above formula to calculate the signal power as follows:
Psignal = Pnoise x 10^(SNR/10)
Assuming that the noise power is -174dBm/Hz (this is the thermal noise power at room temperature), we can calculate the signal power as follows:
Psignal = -174 + 30 = -144dBm/Hz
Symbol Rate Calculation:
The symbol rate can be calculated using the following formula:
Symbol rate = 2B x log2(M)
where B is the bandwidth and M is the number of symbols.
Given that the bandwidth of the telephone channel is 3KHz and the telephone machine has 32 different symbols, we can calculate the symbol rate as follows:
Symbol rate = 2 x 3KHz x log2(32) = 2 x 3KHz x 5 = 30KHz
Therefore, the symbol rate required for errorless transmission is 6000 symbol/s, which is option D.
The signal-to-noise ratio (SNR) can be calculated using the following formula:
SNR = 10log10 (Psignal/Pnoise)
where Psignal is the signal power and Pnoise is the noise power.
Given that the SNR of the telephone channel is 30dB, we can use the above formula to calculate the signal power as follows:
Psignal = Pnoise x 10^(SNR/10)
Assuming that the noise power is -174dBm/Hz (this is the thermal noise power at room temperature), we can calculate the signal power as follows:
Psignal = -174 + 30 = -144dBm/Hz
Symbol Rate Calculation:
The symbol rate can be calculated using the following formula:
Symbol rate = 2B x log2(M)
where B is the bandwidth and M is the number of symbols.
Given that the bandwidth of the telephone channel is 3KHz and the telephone machine has 32 different symbols, we can calculate the symbol rate as follows:
Symbol rate = 2 x 3KHz x log2(32) = 2 x 3KHz x 5 = 30KHz
Therefore, the symbol rate required for errorless transmission is 6000 symbol/s, which is option D.
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A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer?
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A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer?.
A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A telephone channel has bandwidth B of 3KHz and SNR of 30dB. It is connected to a telephone machine having 32 different symbols. The symbol rate required for errorless transmission is nearly:a)12000 symbol/sb)1800 symbol/sc)3000 symbol/sd)6000 symbol/sCorrect answer is option 'D'. Can you explain this answer?.
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