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Consider the function f(x) = |x3| where x is real, then the function f (x) at y = 0 is
  • a)
    continuous but not differentiable
  • b)
    once differentiable but not twice
  • c)
    twice differentiable but not thrice
  • d)
    thrice differentiable
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Consider the functionf(x) = |x3|where x is real, thenthe function f (x...
Given that

It is clear that the funtion is twice differentiable at x = 0 and the other points the function is a polynomial.
Therfore, it is obviously differentiable.
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Most Upvoted Answer
Consider the functionf(x) = |x3|where x is real, thenthe function f (x...
Given that

It is clear that the funtion is twice differentiable at x = 0 and the other points the function is a polynomial.
Therfore, it is obviously differentiable.
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Consider the functionf(x) = |x3|where x is real, thenthe function f (x) at y = 0 isa)continuous but not differentiableb)once differentiable but not twicec)twice differentiable but not thriced)thrice differentiableCorrect answer is option 'C'. Can you explain this answer?
Question Description
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