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Let x and y be independent random variables with binomial distribution B(10, 1 /3) and B(20, 1/3) respectively. E[x + y] is
  • a)
    5
  • b)
    10
  • c)
    15
  • d)
    30
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let x and y be independent random variables with binomial distribution...
 E (x + y) = E (x) + E(y)

Expectation of binomial distribution is np if B(n, p) is the binomial distribution.
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Most Upvoted Answer
Let x and y be independent random variables with binomial distribution...
 E (x + y) = E (x) + E(y)

Expectation of binomial distribution is np if B(n, p) is the binomial distribution.
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Let x and y be independent random variables with binomial distribution B(10, 1 /3) and B(20, 1/3) respectively. E[x + y]isa)5b)10c)15d)30Correct answer is option 'B'. Can you explain this answer?
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