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The probability of throwing 6 at least one in four throws of a die is :
  • a)
    1/6
  • b)
    2/3
  • c)
    625/1296
  • d)
    671/1296
Correct answer is option 'D'. Can you explain this answer?
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The probability of throwing 6 at least one in four throws of a die is ...
Probability of throwing 6 at least once = 1 - probability of not throwing 6.
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The probability of throwing 6 at least one in four throws of a die is ...
Probability of Throwing a 6 in One Throw of a Die

To find the probability of throwing a 6 in one throw of a die, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.

- The number of favorable outcomes is 1 (getting a 6).
- The total number of possible outcomes is 6 (since there are six faces on a die).

Therefore, the probability of throwing a 6 in one throw of a die is 1/6.

Finding the Probability of Not Throwing a 6 in One Throw

To find the probability of not throwing a 6 in one throw, we subtract the probability of throwing a 6 from 1.

- Probability of not throwing a 6 = 1 - 1/6 = 5/6.

Probability of Not Throwing a 6 in Four Throws

Since we want to find the probability of not throwing a 6 in four throws, we can multiply the probability of not throwing a 6 in one throw by itself four times.

- Probability of not throwing a 6 in four throws = (5/6)^4 = 625/1296.

Finding the Probability of Throwing a 6 in Four Throws

To find the probability of throwing a 6 in at least one of the four throws, we subtract the probability of not throwing a 6 in four throws from 1.

- Probability of throwing a 6 in four throws = 1 - 625/1296 = 671/1296.

Therefore, the correct answer is option 'D' - 671/1296.
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The probability of throwing 6 at least one in four throws of a die is :a)1/6b)2/3c)625/1296d)671/1296Correct answer is option 'D'. Can you explain this answer?
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