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The number of metal-metal bonds present in Ir4(CO)12 are:
    Correct answer is '6'. Can you explain this answer?
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    The number of metal-metal bonds present in Ir4(CO)12 are:Correct answe...
    Metal-Metal Bonds in Ir4(CO)12

    Metal-metal bonding is a type of bonding that occurs between two metal atoms. In Ir4(CO)12, there are four iridium (Ir) atoms, and each of them is bonded to each other through metal-metal bonds. Therefore, the total number of metal-metal bonds present in Ir4(CO)12 is six.

    Explanation:

    - Ir4(CO)12 is a chemical compound that contains four iridium (Ir) atoms and twelve carbon monoxide (CO) molecules.
    - The iridium atoms are arranged in a tetrahedral shape, with each iridium atom bonded to the other three iridium atoms.
    - The metal-metal bonds in Ir4(CO)12 are formed due to the overlapping of the d-orbitals of the iridium atoms. This overlapping results in the formation of covalent bonds between the metal atoms.
    - The metal-metal bonds in Ir4(CO)12 are relatively weak compared to the metal-carbon bonds between the iridium atoms and the carbon monoxide molecules.
    - The metal-metal bonds in Ir4(CO)12 are important for the stability and structural integrity of the compound.

    Conclusion:

    In conclusion, Ir4(CO)12 contains six metal-metal bonds. These bonds are formed due to the overlapping of the d-orbitals of the iridium atoms and are important for the stability and structural integrity of the compound.
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    The number of metal-metal bonds present in Ir4(CO)12 are:Correct answe...
    Formula to calculate #m-m bonds = 18n - TVE / 2. Where, TVE- total valence electrons

    For Ir4(CO)12, n=4 as there are 4 Ir metal atoms. 
    TVE= 4(9) + 12(2) = 60. Where 9 and 2 are valence electrons of Ir and CO respectively. 

    #m-m bonds = (18*4) - 60 /2 
                         = 72-60/2 = 12/2 = 6
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    The number of metal-metal bonds present in Ir4(CO)12 are:Correct answer is '6'. Can you explain this answer?
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