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The magnetic moment of a transition metal ion is Therefore the number of unpaired electrons present in it is ?
    Correct answer is '3'. Can you explain this answer?
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    The magnetic moment of a transition metal ion is Therefore the number ...
     
    Magnetic moment =√n(n+2)
    where, n = no. of unpaired electrons.
    given, μ=√15
    ∴ √15= √n(n+2)= 15=n(n+2)
    This is possible only when n=3
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    The magnetic moment of a transition metal ion is Therefore the number ...
     
    Magnetic moment =√n(n+2)
    where, n = no. of unpaired electrons.
    given, μ=√15
    ∴ √15= √n(n+2)= 15=n(n+2)
    This is possible only when n=3
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    The magnetic moment of a transition metal ion is Therefore the number ...
     
    Magnetic moment =√n(n+2)
    where, n = no. of unpaired electrons.
    given, μ=√15
    ∴ √15= √n(n+2)= 15=n(n+2)
    This is possible only when n=3
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    The magnetic moment of a transition metal ion is Therefore the number of unpaired electrons present in it is ?Correct answer is '3'. Can you explain this answer?
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