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An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.
Correct answer is '4.0'. Can you explain this answer?
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Verified Answer
An isolated metal body is illuminated with monochromatic light and is ...
By Einstein's Photoelectric equation
eV=hν−ϕ
where V=1V= cut off voltage
⟹ν= (eV+ϕ)/ h =4eV/h=4×1.6×10−19/6.63×10−34
⟹ν=9.6×1014Hz
eV=hν−ϕ
where V=1V= cut off voltage
⟹ν= (eV+ϕ)/ h =4eV/h=4×1.6×10−19/6.63×10−34
⟹ν=9.6×1014Hz
Most Upvoted Answer
An isolated metal body is illuminated with monochromatic light and is ...
Understanding the Problem
The scenario involves an isolated metal body being illuminated by monochromatic light, resulting in a steady positive potential of 1.0 V. The work function (ϕ) of the metal is given as 3.0 eV.
Concept of Photoelectric Effect
- The photoelectric effect is the phenomenon where electrons are ejected from a metal surface when it absorbs light (photons) of sufficient energy.
- The energy of the incoming photons is given by the equation:
\[ E = h \cdot f \]
where \( E \) is the photon energy, \( h \) is Planck's constant (\( 4.1357 \times 10^{-15} \, \text{eV·s} \)), and \( f \) is the frequency of the light.
Calculating the Photon Energy
- For electrons to be emitted from the metal, the photon energy must exceed the work function of the metal:
\[ E = \phi + W \]
where \( W \) is the work done to move the emitted electron to the positive potential (1.0 V).
- Here, \( \phi = 3.0 \, \text{eV} \) and \( W = 1.0 \, \text{eV} \). Therefore:
\[ E = 3.0 \, \text{eV} + 1.0 \, \text{eV} = 4.0 \, \text{eV} \]
Conclusion
- The frequency of the incident light can thus be calculated using the energy equation:
\[ E = h \cdot f \]
- Since we have determined that the energy of the incident light is 4.0 eV, this confirms that the frequency of the light corresponds to a photon energy of 4.0 eV.
Thus, the frequency of the incident light is indeed 4.0 eV.
The scenario involves an isolated metal body being illuminated by monochromatic light, resulting in a steady positive potential of 1.0 V. The work function (ϕ) of the metal is given as 3.0 eV.
Concept of Photoelectric Effect
- The photoelectric effect is the phenomenon where electrons are ejected from a metal surface when it absorbs light (photons) of sufficient energy.
- The energy of the incoming photons is given by the equation:
\[ E = h \cdot f \]
where \( E \) is the photon energy, \( h \) is Planck's constant (\( 4.1357 \times 10^{-15} \, \text{eV·s} \)), and \( f \) is the frequency of the light.
Calculating the Photon Energy
- For electrons to be emitted from the metal, the photon energy must exceed the work function of the metal:
\[ E = \phi + W \]
where \( W \) is the work done to move the emitted electron to the positive potential (1.0 V).
- Here, \( \phi = 3.0 \, \text{eV} \) and \( W = 1.0 \, \text{eV} \). Therefore:
\[ E = 3.0 \, \text{eV} + 1.0 \, \text{eV} = 4.0 \, \text{eV} \]
Conclusion
- The frequency of the incident light can thus be calculated using the energy equation:
\[ E = h \cdot f \]
- Since we have determined that the energy of the incident light is 4.0 eV, this confirms that the frequency of the light corresponds to a photon energy of 4.0 eV.
Thus, the frequency of the incident light is indeed 4.0 eV.
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An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer?
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An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer?.
An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer?.
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An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer?, a detailed solution for An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? has been provided alongside types of An isolated metal body is illuminated with monochromatic light and is observed to become charged to a steady positive potential 1.0 V with respect to the surrounding. The work function of the metal is 3.0 eV. The frequency of the incident light is ___________________ eV.Correct answer is '4.0'. Can you explain this answer? theory, EduRev gives you an
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