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An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could be
- a)CH₃OH
- b)CH₃CHO
- c)CH₃CH(OH)CH₃
- d)CH₃CH₂CH₂OH
Correct answer is option 'C'. Can you explain this answer?
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An organic compound 'X' on treatment with acidified K₂Cr...
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An organic compound 'X' on treatment with acidified K₂Cr...
Explanation:
The given organic compound X on treatment with acidified KCrO4 gives a compound Y. Compound Y reacts with I and sodium carbonate to form triiodomethane. The compound X could be:
a) CHOH
b) CHCHO
c) CHCH(OH)CH3
d) CH2CHCHOH
Let's analyze each option:
a) CHOH: This is methanol. On treatment with acidified KCrO4, it will give formaldehyde, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option A is incorrect.
b) CHCHO: This is acetaldehyde. On treatment with acidified KCrO4, it will give acetic acid, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option B is incorrect.
c) CHCH(OH)CH3: This is 2-propanol. On treatment with acidified KCrO4, it will give acetone, which can react with I and sodium carbonate to form triiodomethane. Hence, option C is correct.
d) CH2CHCHOH: This is 2-butanol. On treatment with acidified KCrO4, it will give butanone, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option D is incorrect.
Therefore, the correct option is C, which is 2-propanol.
The given organic compound X on treatment with acidified KCrO4 gives a compound Y. Compound Y reacts with I and sodium carbonate to form triiodomethane. The compound X could be:
a) CHOH
b) CHCHO
c) CHCH(OH)CH3
d) CH2CHCHOH
Let's analyze each option:
a) CHOH: This is methanol. On treatment with acidified KCrO4, it will give formaldehyde, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option A is incorrect.
b) CHCHO: This is acetaldehyde. On treatment with acidified KCrO4, it will give acetic acid, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option B is incorrect.
c) CHCH(OH)CH3: This is 2-propanol. On treatment with acidified KCrO4, it will give acetone, which can react with I and sodium carbonate to form triiodomethane. Hence, option C is correct.
d) CH2CHCHOH: This is 2-butanol. On treatment with acidified KCrO4, it will give butanone, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option D is incorrect.
Therefore, the correct option is C, which is 2-propanol.
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An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer?
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An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer?.
An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer?.
Solutions for An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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