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An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could be
- a)CH₃OH
- b)CH₃CHO
- c)CH₃CH(OH)CH₃
- d)CH₃CH₂CH₂OH
Correct answer is option 'C'. Can you explain this answer?
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An organic compound 'X' on treatment with acidified K₂Cr...
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An organic compound 'X' on treatment with acidified K₂Cr...
Explanation:
The given organic compound X on treatment with acidified KCrO4 gives a compound Y. Compound Y reacts with I and sodium carbonate to form triiodomethane. The compound X could be:
a) CHOH
b) CHCHO
c) CHCH(OH)CH3
d) CH2CHCHOH
Let's analyze each option:
a) CHOH: This is methanol. On treatment with acidified KCrO4, it will give formaldehyde, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option A is incorrect.
b) CHCHO: This is acetaldehyde. On treatment with acidified KCrO4, it will give acetic acid, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option B is incorrect.
c) CHCH(OH)CH3: This is 2-propanol. On treatment with acidified KCrO4, it will give acetone, which can react with I and sodium carbonate to form triiodomethane. Hence, option C is correct.
d) CH2CHCHOH: This is 2-butanol. On treatment with acidified KCrO4, it will give butanone, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option D is incorrect.
Therefore, the correct option is C, which is 2-propanol.
The given organic compound X on treatment with acidified KCrO4 gives a compound Y. Compound Y reacts with I and sodium carbonate to form triiodomethane. The compound X could be:
a) CHOH
b) CHCHO
c) CHCH(OH)CH3
d) CH2CHCHOH
Let's analyze each option:
a) CHOH: This is methanol. On treatment with acidified KCrO4, it will give formaldehyde, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option A is incorrect.
b) CHCHO: This is acetaldehyde. On treatment with acidified KCrO4, it will give acetic acid, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option B is incorrect.
c) CHCH(OH)CH3: This is 2-propanol. On treatment with acidified KCrO4, it will give acetone, which can react with I and sodium carbonate to form triiodomethane. Hence, option C is correct.
d) CH2CHCHOH: This is 2-butanol. On treatment with acidified KCrO4, it will give butanone, which cannot undergo further reaction with I and sodium carbonate to form triiodomethane. Hence, option D is incorrect.
Therefore, the correct option is C, which is 2-propanol.
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An organic compound 'X' on treatment with acidified K₂Cr₂O₇ gives a compound 'Y' which reacts with I₂ and sodium carbonate to form triodomethane. The compound 'X' could bea)CH₃OHb)CH₃CHOc)CH₃CH(OH)CH₃d)CH₃CH₂CH₂OHCorrect answer is option 'C'. Can you explain this answer?
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