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Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer?.

Solutions for Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer?, a detailed solution for Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? has been provided alongside types of Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Treatment of A (C5H12O) with concentrated sulphuric acid results in the formation of three alkenes in differing yields. Also, A forms a yellow precipitate on treatment with NaOH/I2. A turns colour of acidified dichromate solution to blue green, forming a new organic compound B which also forms yellow precipitate on treatment with NaOH/I2. The most likely name of A isa)3-methyl-2-butanolb)3-methyl butanolc)2-pentanold)Either (b) or (c)Correct answer is option 'A,C'. Can you explain this answer? tests, examples and also practice JEE tests.