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A bag contains 3 black, 4 white and 2 red balls, all the balls being different. The number of selections of at most 6 balls cotaining balls of all the colours is
  • a)
    42(4!)
  • b)
    26 x 4!
  • c)
    (25-1)(4!)
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?
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A bag contains 3 black, 4 white and 2 red balls, all the balls being d...
The required number of selections.
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A bag contains 3 black, 4 white and 2 red balls, all the balls being d...
Solution:
To solve this problem, we can use the concept of combinations.
Given that the bag contains 3 black, 4 white, and 2 red balls, we need to find the number of selections of at most 6 balls containing balls of all the colors.

1. Selection of balls:
Let's consider the selection of balls in the following way:
- Selecting 0 black balls, 0 white balls, and 0 red balls
- Selecting 1 black ball, 0 white balls, and 0 red balls
- Selecting 0 black balls, 1 white ball, and 0 red balls
- Selecting 0 black balls, 0 white balls, and 1 red ball
- Selecting 1 black ball, 1 white ball, and 0 red balls
- Selecting 1 black ball, 0 white balls, and 1 red ball
- Selecting 0 black balls, 1 white ball, and 1 red ball

2. Selections with 0 black balls:
If we select 0 black balls, we have only one option, which is to select 6 white or red balls. Since we have 4 white balls and 2 red balls, the number of ways to select 6 balls is given by:
C(6, 6) + C(6, 6) = 1 + 1 = 2

3. Selections with 1 black ball:
If we select 1 black ball, we have 3 options for selecting the black ball and 5 options for selecting the remaining balls (either white or red). The number of ways to select these balls is given by:
C(3, 1) * C(5, 5) + C(3, 1) * C(5, 5) = 3 + 3 = 6

4. Selections with 0 white balls:
If we select 0 white balls, we have only one option, which is to select 6 black or red balls. Since we have 3 black balls and 2 red balls, the number of ways to select 6 balls is given by:
C(6, 6) + C(6, 6) = 1 + 1 = 2

5. Selections with 1 white ball:
If we select 1 white ball, we have 4 options for selecting the white ball and 5 options for selecting the remaining balls (either black or red). The number of ways to select these balls is given by:
C(4, 1) * C(5, 5) + C(4, 1) * C(5, 5) = 4 + 4 = 8

6. Selections with 0 red balls:
If we select 0 red balls, we have only one option, which is to select 6 black or white balls. Since we have 3 black balls and 4 white balls, the number of ways to select 6 balls is given by:
C(6, 6) + C(6, 6) = 1 + 1 = 2

7. Selections with 1 red ball:
If we select 1 red ball, we have 2 options for selecting the red ball and 5 options for selecting the remaining balls (either black or white). The
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A bag contains 3 black, 4 white and 2 red balls, all the balls being d...
The required number of selections.
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A bag contains 3 black, 4 white and 2 red balls, all the balls being different. The number of selections of at most 6 balls cotaining balls of all the colours isa)42(4!)b)26 x 4!c)(25-1)(4!)d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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A bag contains 3 black, 4 white and 2 red balls, all the balls being different. The number of selections of at most 6 balls cotaining balls of all the colours isa)42(4!)b)26 x 4!c)(25-1)(4!)d)none of theseCorrect answer is option 'A'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about A bag contains 3 black, 4 white and 2 red balls, all the balls being different. The number of selections of at most 6 balls cotaining balls of all the colours isa)42(4!)b)26 x 4!c)(25-1)(4!)d)none of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 3 black, 4 white and 2 red balls, all the balls being different. The number of selections of at most 6 balls cotaining balls of all the colours isa)42(4!)b)26 x 4!c)(25-1)(4!)d)none of theseCorrect answer is option 'A'. Can you explain this answer?.
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