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In a photoelectric effect set up two metals with work function φ1 and φ2 are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eV and the φ1 = 1.5eV. Find φ2. (in eV)
Correct answer is '6.5'. Can you explain this answer?
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In a photoelectric effect set up two metals with work function φ1a...
The correct answer is: 6.5
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In a photoelectric effect set up two metals with work function φ1a...
A work function is the minimum amount of energy required to remove an electron from the surface of a material. In a photoelectric effect setup, two metals with different work functions can be used.
Let's say we have Metal A with a work function of ΦA and Metal B with a work function of ΦB.
In this setup, both metals are exposed to light of a certain frequency or energy. If the energy of the incident photons is greater than the work function of a metal, electrons can be ejected from the surface of that metal.
If the incident light has enough energy, electrons from both Metal A and Metal B can be ejected. However, the number of ejected electrons and their kinetic energy will depend on the intensity and frequency of the incident light, as well as the work function of each metal.
The photoelectric effect can be observed by measuring the current or the number of ejected electrons as a function of the intensity or frequency of the incident light. This experiment can provide valuable information about the properties of the metals and the nature of light.
Let's say we have Metal A with a work function of ΦA and Metal B with a work function of ΦB.
In this setup, both metals are exposed to light of a certain frequency or energy. If the energy of the incident photons is greater than the work function of a metal, electrons can be ejected from the surface of that metal.
If the incident light has enough energy, electrons from both Metal A and Metal B can be ejected. However, the number of ejected electrons and their kinetic energy will depend on the intensity and frequency of the incident light, as well as the work function of each metal.
The photoelectric effect can be observed by measuring the current or the number of ejected electrons as a function of the intensity or frequency of the incident light. This experiment can provide valuable information about the properties of the metals and the nature of light.
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In a photoelectric effect set up two metals with work function φ1a...
Solution=
eVs1=hv- Φ1
eVs2=hv- Φ2
eVs1= eVs2
eVs1/eVs2 = hv- Φ2/ hv- Φ1=1/2
2hv-2Φ2 = 1hv- Φ1
2Φ2 = hv+ Φ1
2Φ2 = 5+1.5
2Φ2 = 6.5eV
Φ2 = 3.25eV
The correct answer would be 3.25eV
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In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer?
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In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer?.
In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric effect set up two metals with work function φ1andφ2are used. For the same value of incident frequency, the stopping potential for metal 1 is twice that for metal 2. If the incident energy is 5eVand theφ1= 1.5eV. Findφ2.(ineV)Correct answer is '6.5'. Can you explain this answer?.
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