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Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.
  • a)
    3/2 O2(g) → O3(g)
  • b)
    1/8 S8(s) + O2(g) → SO2(g)
  • c)
    2H2(g) + O2(g) → 2H2O(l)
  • d)
    2C(g) + 3H2(g) → C2H6(g)
Correct answer is option 'A,B'. Can you explain this answer?
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Choose the reaction(s) from the following options, for which the stand...
Enthalpy of formation is defined as enthalpy change for formation of 1 mole of substance from its elements, present in their natural most stable form.
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Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.a)3/2 O2(g)→ O3(g)b)1/8 S8(s) + O2(g)→ SO2(g)c)2H2(g) + O2(g) → 2H2O(l)d)2C(g) + 3H2(g) → C2H6(g)Correct answer is option 'A,B'. Can you explain this answer?
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Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.a)3/2 O2(g)→ O3(g)b)1/8 S8(s) + O2(g)→ SO2(g)c)2H2(g) + O2(g) → 2H2O(l)d)2C(g) + 3H2(g) → C2H6(g)Correct answer is option 'A,B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.a)3/2 O2(g)→ O3(g)b)1/8 S8(s) + O2(g)→ SO2(g)c)2H2(g) + O2(g) → 2H2O(l)d)2C(g) + 3H2(g) → C2H6(g)Correct answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Choose the reaction(s) from the following options, for which the standard enthalpy of reaction is equal to the standard enthalpy of formation.a)3/2 O2(g)→ O3(g)b)1/8 S8(s) + O2(g)→ SO2(g)c)2H2(g) + O2(g) → 2H2O(l)d)2C(g) + 3H2(g) → C2H6(g)Correct answer is option 'A,B'. Can you explain this answer?.
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