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Indefinite integral of 1/cos^6x sin^6x?
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Indefinite integral of 1/cos^6x sin^6x?
Indefinite Integral of 1/cos^6x sin^6x


When finding the indefinite integral of a function, we aim to find the antiderivative of the function. In other words, we look for a function whose derivative is the given function. In this case, we are given the function 1/cos^6x sin^6x and we need to find its indefinite integral.


Step 1: Simplify the Function


Before we can integrate the function, we need to simplify it. We can do this by using trigonometric identities. We know that:



  • cos^2x + sin^2x = 1

  • 1/cos^2x = sec^2x

  • 1/sin^2x = cosec^2x



Using these identities, we can simplify 1/cos^6x sin^6x as follows:


1/cos^6x sin^6x = (1/cos^2x)^3 (1/sin^2x)^3


Substituting the identities for 1/cos^2x and 1/sin^2x:


(sec^2x)^3 (cosec^2x)^3 = sec^6x cosec^6x


So, 1/cos^6x sin^6x = sec^6x cosec^6x


Step 2: Use the Power Reduction Formula


Now that we have simplified the function, we can use the power reduction formula to integrate it. The power reduction formula is:


sin^m x cos^n x dx = (1/2) sin^(m-1) x cos^(n+1) x dx - (m-1)/(2n+2) sin^(m-3) x cos^(n+2) x dx


Using this formula with m = n = 3, we get:


sec^6x cosec^6x dx = (1/2) sec^3x cosec^7x dx - (3/10) sec^3x cosec^9x dx


Step 3: Integrate the Function


Now that we have simplified the function and applied the power reduction formula, we can integrate it. Integrating the first term:


(1/2) sec^3x cosec^7x dx = (1/2) ∫ sec^3x cosec^7x dx


We can use the substitution u = sin x to solve this integral. Using the identity 1 + tan^2x = sec^2x, we can write:


∫ sec^3x dx = ∫ sec^3x (1 + tan^2x)/ (1 + tan^2x) dx


Substituting u = sin x:


∫ sec^3x dx = ∫ (1 + tan^2x)/ (
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Indefinite integral of 1/cos^6x sin^6x?
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Indefinite integral of 1/cos^6x sin^6x?
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