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The isoelectric point of lysine which has pKb 9.06, pKa 2.16 and pKR as 10.54 is ____________[Answer upto two decimal places]
- a)
- b)
- c)
- d)
- e)
Correct answer is '9.8'. Can you explain this answer?
Verified Answer
The isoelectric point of lysine which has pKb9.06, pKa2.16 and pKR as ...
Isoelectric point: In proteins the isoelectric point (pI) is defined as the pH at which a protein has no net charge.
In case of a basic amino acid, pI lies in between the pKb and pKR and is equal to the average of pKb and pKR(10.54+9.06)/2 = 9.77 = ~ 9.8.
In case of an acidic amino acid, pI lies in between the pKa and pKR and is equal to the average of pKa and pKR.
In case of a neutral amino acid, pI lies in between the pKb and pKa and is equal to the average of pKa and pKb.
In case of a basic amino acid, pI lies in between the pKb and pKR and is equal to the average of pKb and pKR(10.54+9.06)/2 = 9.77 = ~ 9.8.
In case of an acidic amino acid, pI lies in between the pKa and pKR and is equal to the average of pKa and pKR.
In case of a neutral amino acid, pI lies in between the pKb and pKa and is equal to the average of pKa and pKb.
Most Upvoted Answer
The isoelectric point of lysine which has pKb9.06, pKa2.16 and pKR as ...
Isoelectric point (pI) is the pH at which a molecule carries no net electrical charge. It can be determined by calculating the average of the two pKa values that flank the pI.
Given data:
pKb = 9.06
pKa2 = 2.16
pKR = 10.54
To find the isoelectric point of lysine, we need to consider the different ionization states of the molecule at different pH values.
1. Determine the ionization states of lysine:
- At low pH (<2.16): all="" three="" functional="" groups="" (-nh3+,="" -cooh,="" -nh2)="" are="">
- At pH between 2.16 and 9.06: The amino group (-NH2) loses a proton and becomes neutral (-NH3+ -> -NH2).
- At pH between 9.06 and 10.54: The carboxyl group (-COOH) loses a proton and becomes neutral (-COOH -> -COO-).
- At high pH (>10.54): The side chain amino group (-NH2) loses a proton and becomes negatively charged (-NH2 -> -NH-).
2. Calculate the pI using the two pKa values:
- The pI is the average of the two pKa values that flank the pI.
- In this case, the two pKa values are pKa2 (2.16) and pKR (10.54).
- Therefore, the pI = (pKa2 + pKR) / 2 = (2.16 + 10.54) / 2 = 12.70 / 2 = 6.35.
3. Convert the pI value to pH:
- Since pH can range from 0 to 14, the pI value of 6.35 is not within this range.
- However, we know that the pI of an amino acid can be calculated by subtracting the pI value from 14.
- Therefore, the pH at the isoelectric point of lysine is 14 - 6.35 = 7.65.
4. Determine the correct answer:
- The correct answer is between 9.71 and 9.79, which is not consistent with the calculated pI value of 7.65.
- It seems that there might be an error in the given information or the correct answer.
In conclusion, based on the given data, the calculated pI of lysine is 7.65, which does not match the correct answer range provided. It is recommended to review the data and confirm the correct answer.
Given data:
pKb = 9.06
pKa2 = 2.16
pKR = 10.54
To find the isoelectric point of lysine, we need to consider the different ionization states of the molecule at different pH values.
1. Determine the ionization states of lysine:
- At low pH (<2.16): all="" three="" functional="" groups="" (-nh3+,="" -cooh,="" -nh2)="" are="">
- At pH between 2.16 and 9.06: The amino group (-NH2) loses a proton and becomes neutral (-NH3+ -> -NH2).
- At pH between 9.06 and 10.54: The carboxyl group (-COOH) loses a proton and becomes neutral (-COOH -> -COO-).
- At high pH (>10.54): The side chain amino group (-NH2) loses a proton and becomes negatively charged (-NH2 -> -NH-).
2. Calculate the pI using the two pKa values:
- The pI is the average of the two pKa values that flank the pI.
- In this case, the two pKa values are pKa2 (2.16) and pKR (10.54).
- Therefore, the pI = (pKa2 + pKR) / 2 = (2.16 + 10.54) / 2 = 12.70 / 2 = 6.35.
3. Convert the pI value to pH:
- Since pH can range from 0 to 14, the pI value of 6.35 is not within this range.
- However, we know that the pI of an amino acid can be calculated by subtracting the pI value from 14.
- Therefore, the pH at the isoelectric point of lysine is 14 - 6.35 = 7.65.
4. Determine the correct answer:
- The correct answer is between 9.71 and 9.79, which is not consistent with the calculated pI value of 7.65.
- It seems that there might be an error in the given information or the correct answer.
In conclusion, based on the given data, the calculated pI of lysine is 7.65, which does not match the correct answer range provided. It is recommended to review the data and confirm the correct answer.
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The isoelectric point of lysine which has pKb9.06, pKa2.16 and pKR as 10.54 is ____________[Answer upto two decimal places]a)b)c)d)e)Correct answer is '9.8'. Can you explain this answer? for IIT JAM 2025 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The isoelectric point of lysine which has pKb9.06, pKa2.16 and pKR as 10.54 is ____________[Answer upto two decimal places]a)b)c)d)e)Correct answer is '9.8'. Can you explain this answer? covers all topics & solutions for IIT JAM 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The isoelectric point of lysine which has pKb9.06, pKa2.16 and pKR as 10.54 is ____________[Answer upto two decimal places]a)b)c)d)e)Correct answer is '9.8'. Can you explain this answer?.
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