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Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.
- a)1.8 × 10–12 m
- b)2.8 × 10–12 m
- c)3.8 × 10–12 m
- d)5.4 × 10–12 m
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Smallest possible uncertainty in position of the electron moving with ...
Given, v = 3 × 107 m/s
Let Δxmin be the minimum uncertainty in position of the electron and Δp the maximum uncertainty in the momentum of the electron.
Let Δxmin be the minimum uncertainty in position of the electron and Δp the maximum uncertainty in the momentum of the electron.
Thus, we have,
= 0.03867 × 0.9949 × 10–10 m
= 3.8 × 10–12 m
The correct answer is: 3.8 × 10–12 m
= 0.03867 × 0.9949 × 10–10 m
= 3.8 × 10–12 m
The correct answer is: 3.8 × 10–12 m
Most Upvoted Answer
Smallest possible uncertainty in position of the electron moving with ...
To determine the smallest possible uncertainty in the position of an electron moving with velocity 3 m/s, we can use the Heisenberg uncertainty principle.
According to the Heisenberg uncertainty principle, the product of the uncertainty in position and the uncertainty in momentum (mass times velocity) must be greater than or equal to Planck's constant (h) divided by 4π.
Δx * Δp ≥ h/4π
Since we know the velocity of the electron is 3 m/s, we can calculate the momentum using the equation:
p = m * v
where m is the mass of the electron (9.11 x 10^-31 kg) and v is the velocity (3 m/s).
p = (9.11 x 10^-31 kg) * (3 m/s)
p = 2.733 x 10^-30 kg·m/s
Now we can rearrange the uncertainty principle equation to solve for the uncertainty in position:
Δx ≥ (h/4π) / Δp
Δx ≥ (6.626 x 10^-34 J·s / (4π)) / (2.733 x 10^-30 kg·m/s)
Δx ≥ 6.06 x 10^-5 m
Therefore, the smallest possible uncertainty in the position of the electron moving with velocity 3 m/s is approximately 6.06 x 10^-5 meters.
According to the Heisenberg uncertainty principle, the product of the uncertainty in position and the uncertainty in momentum (mass times velocity) must be greater than or equal to Planck's constant (h) divided by 4π.
Δx * Δp ≥ h/4π
Since we know the velocity of the electron is 3 m/s, we can calculate the momentum using the equation:
p = m * v
where m is the mass of the electron (9.11 x 10^-31 kg) and v is the velocity (3 m/s).
p = (9.11 x 10^-31 kg) * (3 m/s)
p = 2.733 x 10^-30 kg·m/s
Now we can rearrange the uncertainty principle equation to solve for the uncertainty in position:
Δx ≥ (h/4π) / Δp
Δx ≥ (6.626 x 10^-34 J·s / (4π)) / (2.733 x 10^-30 kg·m/s)
Δx ≥ 6.06 x 10^-5 m
Therefore, the smallest possible uncertainty in the position of the electron moving with velocity 3 m/s is approximately 6.06 x 10^-5 meters.
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Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer?
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Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer?.
Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Smallest possible uncertainty in position of the electron moving with velocity 3 × 107 m/s. Given, h = 6.63 × 10–34 Js, m0 = 9.1 × 10–31 kg.a)1.8 × 10–12mb)2.8 × 10–12mc)3.8 × 10–12md)5.4 × 10–12mCorrect answer is option 'C'. Can you explain this answer?.
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