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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:
- a)3300 Å
- b)4400 Å
- c)5500 Å
- d)6600 Å
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In an experiment of single slit diffraction pattern, first minimum for...
Write the expression for the first minima of red.
...(1)
Write the expression for maxima for a wavelength λ2.
...(2)
As the light coincides, So compare (1) and (2).
...(1)Write the expression for maxima for a wavelength λ2.
...(2)As the light coincides, So compare (1) and (2).
Most Upvoted Answer
In an experiment of single slit diffraction pattern, first minimum for...
Ångstrom and the distance between the slit and the screen is 1.2 meters, what is the wavelength of the other wavelength?
In a single slit diffraction pattern, the location of the first minimum can be determined using the equation:
sin(θ) = (m * λ) / (d)
Where:
θ is the angle of the first minimum,
m is the order of the minimum (in this case, m = 1),
λ is the wavelength of the light, and
d is the distance between the slit and the screen.
For the first minimum of red light (wavelength = 6600 Ångstrom), we can substitute the given values into the equation:
sin(θ) = (1 * 6600 Ångstrom) / (1.2 meters)
Now, we need to find the wavelength of the other light that coincides with the first maximum of the red light. For the first maximum, the angle is given by:
sin(θ) = (m * λ) / (d)
Since the first maximum occurs at the same angle as the first minimum for the other wavelength, we can equate the two equations:
(1 * λ) / (d) = (1 * 6600 Ångstrom) / (1.2 meters)
We can rearrange the equation to solve for the wavelength of the other light:
λ = (6600 Ångstrom) / (1.2 meters)
Converting Ångstrom to meters:
1 Ångstrom = 1 x 10^-10 meters
λ = (6600 x 10^-10 meters) / (1.2 meters)
λ = 5.5 x 10^-7 meters
λ = 550 nm
Therefore, the wavelength of the other light is 550 nm.
In a single slit diffraction pattern, the location of the first minimum can be determined using the equation:
sin(θ) = (m * λ) / (d)
Where:
θ is the angle of the first minimum,
m is the order of the minimum (in this case, m = 1),
λ is the wavelength of the light, and
d is the distance between the slit and the screen.
For the first minimum of red light (wavelength = 6600 Ångstrom), we can substitute the given values into the equation:
sin(θ) = (1 * 6600 Ångstrom) / (1.2 meters)
Now, we need to find the wavelength of the other light that coincides with the first maximum of the red light. For the first maximum, the angle is given by:
sin(θ) = (m * λ) / (d)
Since the first maximum occurs at the same angle as the first minimum for the other wavelength, we can equate the two equations:
(1 * λ) / (d) = (1 * 6600 Ångstrom) / (1.2 meters)
We can rearrange the equation to solve for the wavelength of the other light:
λ = (6600 Ångstrom) / (1.2 meters)
Converting Ångstrom to meters:
1 Ångstrom = 1 x 10^-10 meters
λ = (6600 x 10^-10 meters) / (1.2 meters)
λ = 5.5 x 10^-7 meters
λ = 550 nm
Therefore, the wavelength of the other light is 550 nm.
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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer?
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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer?.
In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer?.
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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å , then wavelength of first maximum will be:a)3300 Åb)4400 Åc)5500 Åd)6600 ÅCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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