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In a single-slit diffraction experiment, the width of the slit is made double its original width. The central maximum of the diffraction pattern will become
  • a)
    narrower and fainter
  • b)
    narrower and brighter
  • c)
    broader and fainter
  • d)
    broader and brighter
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a single-slit diffraction experiment, the width of the slit is made...
The angular width of the central maximum is 2λ/a, where a is the width of the slit. If the value of a is doubled, the angular width of the central maximum decreases to half its earlier value. This implies that the central maximum becomes much sharper. Furthermore if a is doubled, the intensity of the central maximum becomes four times. Thus the central maximum becomes much sharper (narrow) and brighter.
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In a single-slit diffraction experiment, the width of the slit is made...
Explanation:
When the width of the slit is made double its original width, the light waves passing through the slit will diffract more and spread out more. This will result in changes in the diffraction pattern.

Change in Intensity of the Central Maximum:
The intensity of the central maximum is directly proportional to the square of the amplitude of the light waves passing through the slit. Since the amplitude of the light waves passing through the slit remains the same, the intensity of the central maximum will remain the same.

Change in Width of the Central Maximum:
The width of the central maximum is inversely proportional to the width of the slit. When the width of the slit is made double, the width of the central maximum will be halved. Therefore, the central maximum will become narrower.

Change in Width of the Secondary Maxima:
The width of the secondary maxima is directly proportional to the width of the slit. When the width of the slit is made double, the width of the secondary maxima will also be doubled. Therefore, the secondary maxima will become broader.

Change in Intensity of the Secondary Maxima:
The intensity of the secondary maxima is directly proportional to the square of the amplitude of the light waves passing through the slit. Since the amplitude of the light waves passing through the slit remains the same, the intensity of the secondary maxima will remain the same.

Conclusion:
Therefore, the central maximum will become narrower and brighter, while the secondary maxima will become broader and remain of the same intensity.
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In a single-slit diffraction experiment, the width of the slit is made double its original width. The central maximum of the diffraction pattern will becomea)narrower and fainterb)narrower and brighterc)broader and fainterd)broader and brighterCorrect answer is option 'B'. Can you explain this answer?
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