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If cot A = 12/5, then (sin A + cos A) × cosec A is:
  • a)
    12/5
  • b)
    17/5
  • c)
    11/5
  • d)
    2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If cot A = 12/5, then (sin A + cos A) × cosec A is:a)12/5b)17/5c...
⇒ (sin A + cosA) × cosecA = (sinA + cosA) × (1/sinA) = 1 + (cosA/sinA) = 1 + cotA = 1 + (12/5) = 17/5
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Most Upvoted Answer
If cot A = 12/5, then (sin A + cos A) × cosec A is:a)12/5b)17/5c...
To find (sin A cos A), we can use the identity sin^2 A + cos^2 A = 1.

First, we need to find sin A and cos A individually.

Given cot A = 12/5, we can use the reciprocal identity cot A = cos A/sin A to find sin A and cos A.

cot A = 12/5
cos A/sin A = 12/5
cos A = 12/5 * sin A

Now, we can substitute this value of cos A into the identity sin^2 A + cos^2 A = 1.

sin^2 A + (12/5 * sin A)^2 = 1
sin^2 A + (144/25) * sin^2 A = 1
(25/25) * sin^2 A + (144/25) * sin^2 A = 1
(169/25) * sin^2 A = 1
sin^2 A = 25/169
sin A = ±sqrt(25/169) = ±5/13

Now, substitute the value of sin A into the equation cos A = 12/5 * sin A to find cos A.

cos A = 12/5 * (±5/13) = ±60/65 = ±12/13

Therefore, (sin A cos A) = (±5/13) * (±12/13) = ±60/169.
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